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A metre bridge is balanced by putting 20 resistance in the left gap and 40 ohm in the right gap. If the 40 ohm resistance is now shunted with 40 ohm resistance the shunt in null point will be A)16.67cm towards the left end B)16.67cm towards the right end C)1.667cm towards the left end D)1.667cm towards the right end?
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A metre bridge is balanced by putting 20 resistance in the left gap an...
Solution:
Given data:
Resistance in the left gap, R1 = 20 ohm
Resistance in the right gap, R2 = 40 ohm
Shunted resistance, R' = 40 ohm
Let, l1 and l2 be the lengths of the metre bridge on the left and right side of the null point, respectively.
To find: The position of the null point after shunting the resistance.
Assumption:
The resistance of the wire of the metre bridge is negligible.
The unknown resistance (X) is also negligible.
The current passes through the galvanometer and the bridge wire from left to right.
Steps:
1. Calculation of resistance of the bridge wire:
Resistance of the bridge wire, R3 = R1 + R2 = 20 + 40 = 60 ohm
2. Calculation of balancing length:
Balancing length, l = (R2/R3) × 100 cm = (40/60) × 100 = 66.67 cm
This means, the null point is 66.67 cm away from the left end of the wire.
3. Calculation of resistance of the left part of the bridge wire:
Resistance of the left part of the bridge wire, Rl = (l/l1) × R3 = (66.67/l1) × 60
4. Calculation of resistance of the right part of the bridge wire:
Resistance of the right part of the bridge wire, Rr = (l/l2) × R3 = (66.67/l2) × 60
5. Calculation of equivalent resistance of the right part of the bridge wire after shunting:
Equivalent resistance of the right part of the bridge wire after shunting, Rr' = (Rr × R')/(Rr + R') = (66.67/l2 × 40)/(66.67/l2 + 40)
6. Calculation of the new balancing length:
New balancing length, l' = (Rr'/Rl+Rr') × l
= [(66.67/l2 × 40)/(66.67/l2 + 40)] / [(66.67/l1 × 60)/(66.67/l1 + (66.67/l2 × 40)/(66.67/l2 + 40))] × 66.67
7. Simplification of the above equation:
After simplification, we get:
l' = 60/3.6 + l2
l' = 16.67 + l2
8. Calculation of the position of the null point after shunting:
As per the question, the shunted resistance is on the right side. So, the null point will shift towards the right end of the wire.
Therefore, the position of the null point after shunting = l2 - l'
= l2 - (16.67 + l2)
= -16.67 cm
Hence, the answer is option (D) 1.667cm towards the right end.
Conclusion:
Thus, the position of the null point after shunting the resistance is 1.667cm towards the right end of the wire.
Given data:
Resistance in the left gap, R1 = 20 ohm
Resistance in the right gap, R2 = 40 ohm
Shunted resistance, R' = 40 ohm
Let, l1 and l2 be the lengths of the metre bridge on the left and right side of the null point, respectively.
To find: The position of the null point after shunting the resistance.
Assumption:
The resistance of the wire of the metre bridge is negligible.
The unknown resistance (X) is also negligible.
The current passes through the galvanometer and the bridge wire from left to right.
Steps:
1. Calculation of resistance of the bridge wire:
Resistance of the bridge wire, R3 = R1 + R2 = 20 + 40 = 60 ohm
2. Calculation of balancing length:
Balancing length, l = (R2/R3) × 100 cm = (40/60) × 100 = 66.67 cm
This means, the null point is 66.67 cm away from the left end of the wire.
3. Calculation of resistance of the left part of the bridge wire:
Resistance of the left part of the bridge wire, Rl = (l/l1) × R3 = (66.67/l1) × 60
4. Calculation of resistance of the right part of the bridge wire:
Resistance of the right part of the bridge wire, Rr = (l/l2) × R3 = (66.67/l2) × 60
5. Calculation of equivalent resistance of the right part of the bridge wire after shunting:
Equivalent resistance of the right part of the bridge wire after shunting, Rr' = (Rr × R')/(Rr + R') = (66.67/l2 × 40)/(66.67/l2 + 40)
6. Calculation of the new balancing length:
New balancing length, l' = (Rr'/Rl+Rr') × l
= [(66.67/l2 × 40)/(66.67/l2 + 40)] / [(66.67/l1 × 60)/(66.67/l1 + (66.67/l2 × 40)/(66.67/l2 + 40))] × 66.67
7. Simplification of the above equation:
After simplification, we get:
l' = 60/3.6 + l2
l' = 16.67 + l2
8. Calculation of the position of the null point after shunting:
As per the question, the shunted resistance is on the right side. So, the null point will shift towards the right end of the wire.
Therefore, the position of the null point after shunting = l2 - l'
= l2 - (16.67 + l2)
= -16.67 cm
Hence, the answer is option (D) 1.667cm towards the right end.
Conclusion:
Thus, the position of the null point after shunting the resistance is 1.667cm towards the right end of the wire.
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A metre bridge is balanced by putting 20 resistance in the left gap an...
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A metre bridge is balanced by putting 20 resistance in the left gap and 40 ohm in the right gap. If the 40 ohm resistance is now shunted with 40 ohm resistance the shunt in null point will be A)16.67cm towards the left end B)16.67cm towards the right end C)1.667cm towards the left end D)1.667cm towards the right end?
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A metre bridge is balanced by putting 20 resistance in the left gap and 40 ohm in the right gap. If the 40 ohm resistance is now shunted with 40 ohm resistance the shunt in null point will be A)16.67cm towards the left end B)16.67cm towards the right end C)1.667cm towards the left end D)1.667cm towards the right end? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A metre bridge is balanced by putting 20 resistance in the left gap and 40 ohm in the right gap. If the 40 ohm resistance is now shunted with 40 ohm resistance the shunt in null point will be A)16.67cm towards the left end B)16.67cm towards the right end C)1.667cm towards the left end D)1.667cm towards the right end? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A metre bridge is balanced by putting 20 resistance in the left gap and 40 ohm in the right gap. If the 40 ohm resistance is now shunted with 40 ohm resistance the shunt in null point will be A)16.67cm towards the left end B)16.67cm towards the right end C)1.667cm towards the left end D)1.667cm towards the right end?.
A metre bridge is balanced by putting 20 resistance in the left gap and 40 ohm in the right gap. If the 40 ohm resistance is now shunted with 40 ohm resistance the shunt in null point will be A)16.67cm towards the left end B)16.67cm towards the right end C)1.667cm towards the left end D)1.667cm towards the right end? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A metre bridge is balanced by putting 20 resistance in the left gap and 40 ohm in the right gap. If the 40 ohm resistance is now shunted with 40 ohm resistance the shunt in null point will be A)16.67cm towards the left end B)16.67cm towards the right end C)1.667cm towards the left end D)1.667cm towards the right end? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A metre bridge is balanced by putting 20 resistance in the left gap and 40 ohm in the right gap. If the 40 ohm resistance is now shunted with 40 ohm resistance the shunt in null point will be A)16.67cm towards the left end B)16.67cm towards the right end C)1.667cm towards the left end D)1.667cm towards the right end?.
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A metre bridge is balanced by putting 20 resistance in the left gap and 40 ohm in the right gap. If the 40 ohm resistance is now shunted with 40 ohm resistance the shunt in null point will be A)16.67cm towards the left end B)16.67cm towards the right end C)1.667cm towards the left end D)1.667cm towards the right end?, a detailed solution for A metre bridge is balanced by putting 20 resistance in the left gap and 40 ohm in the right gap. If the 40 ohm resistance is now shunted with 40 ohm resistance the shunt in null point will be A)16.67cm towards the left end B)16.67cm towards the right end C)1.667cm towards the left end D)1.667cm towards the right end? has been provided alongside types of A metre bridge is balanced by putting 20 resistance in the left gap and 40 ohm in the right gap. If the 40 ohm resistance is now shunted with 40 ohm resistance the shunt in null point will be A)16.67cm towards the left end B)16.67cm towards the right end C)1.667cm towards the left end D)1.667cm towards the right end? theory, EduRev gives you an
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