25 mL of a solution of barium hydroxide on titration with 0.1 molar so...
Ba(OH)2+2HCl→BaCl2+2H2O
M1V1X1→M2V2X2
(x1 & x2 =v.f)
M1X25X2=0.1X35X1
∴M1=3.550
⇒0.07
Hence (c) is the correct answer.
25 mL of a solution of barium hydroxide on titration with 0.1 molar so...
To find the molarity of the barium hydroxide solution, we can use the equation:
M1V1 = M2V2
Where:
M1 = molarity of the hydrochloric acid
V1 = volume of the hydrochloric acid used
M2 = molarity of the barium hydroxide
V2 = volume of the barium hydroxide used
Given:
M1 = 0.1 M hydrochloric acid
V1 = 35 mL
V2 = 25 mL
Substituting the values into the equation:
(0.1 M)(35 mL) = M2(25 mL)
Simplifying the equation:
3.5 mL = M2(25 mL)
Dividing both sides of the equation by 25 mL:
M2 = 3.5 mL / 25 mL
M2 = 0.14 M
Therefore, the molarity of the barium hydroxide solution is 0.14 M, which corresponds to option (d).