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Hybridizat ion of Ni(II) in K2[NiBr4] is:
  • a)
    dsp2
  • b)
    sp3
  • c)
    sp2d
  • d)
    d3s
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Hybridizat ion of Ni(II) in K2[NiBr4] is:a)dsp2b)sp3c)sp2dd)d3sCorrect...
- In K2[NiBr4], the nickel ion is surrounded by four bromide ions.
- The electronic configuration of Ni(II) is 3d8 4s2.
- To form the complex, the nickel ion utilizes one 4s and three 4p orbitals to hybridize into four sp3 hybrid orbitals.
- The hybrid orbitals are then used to form sigma bonds with the four bromide ions.
- Therefore, the hybridization of Ni(II) in K2[NiBr4] is sp3.
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Most Upvoted Answer
Hybridizat ion of Ni(II) in K2[NiBr4] is:a)dsp2b)sp3c)sp2dd)d3sCorrect...
Hybridization of Ni(II) in K2[NiBr4] is sp3.

Explanation:
- In K2[NiBr4], the nickel ion is surrounded by four bromide ions.
- The electronic configuration of Ni(II) is 3d8 4s2.
- To form the complex, the nickel ion utilizes one 4s and three 4p orbitals to hybridize into four sp3 hybrid orbitals.
- The hybrid orbitals are then used to form sigma bonds with the four bromide ions.
- Therefore, the hybridization of Ni(II) in K2[NiBr4] is sp3.
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Community Answer
Hybridizat ion of Ni(II) in K2[NiBr4] is:a)dsp2b)sp3c)sp2dd)d3sCorrect...
SP3 hybridization
i) EC of Ni+2 is 3d8
ii) Br- is weak ligand so pairing of electron is not possible.
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