JEE Exam > JEE Questions > a ball thrown in air follows a path given by ...
Start Learning for Free
a ball thrown in air follows a path given by y=x/√3-3gx^2/8 met. where xaxis is taken along the horizontal and yaxis long the vertical . the maximum displacement of the ball along x direction for which displacement along y is zero
Most Upvoted Answer
a ball thrown in air follows a path given by y=x/√3-3gx^2/8 met. where...
Solution:
To find the maximum displacement of the ball along the x-direction when the displacement along the y-direction is zero, we need to set the equation equal to zero and solve for x. Let's break down the problem step by step.
Step 1: Set the equation equal to zero.
y = x/√3 - 3gx^2/8
Since we want to find the maximum displacement of x when y is zero, we can set y equal to zero and solve for x.
0 = x/√3 - 3gx^2/8
Step 2: Simplify the equation.
To simplify the equation, we can multiply the entire equation by 8 to eliminate the fractions.
0 = 8(x/√3) - 8(3gx^2/8)
0 = 8x/√3 - 3gx^2
Step 3: Rearrange the equation.
To make the equation easier to work with, let's rearrange it.
3gx^2 = 8x/√3
Step 4: Square both sides of the equation.
To eliminate the square root, we can square both sides of the equation.
(3gx^2)^2 = (8x/√3)^2
9g^2x^4 = 64x^2/3
Step 5: Simplify the equation.
To simplify the equation, we can multiply both sides by 3 to eliminate the fraction.
27g^2x^4 = 64x^2
Step 6: Solve for x.
To solve for x, we can divide both sides of the equation by x^2.
27g^2x^2 = 64
x^2 = 64 / 27g^2
x = ±√(64 / 27g^2)
Step 7: Determine the maximum displacement.
Since we are looking for the maximum displacement along the x-direction, we only consider the positive value of x.
Therefore, the maximum displacement of the ball along the x-direction for which the displacement along the y-direction is zero is given by:
x = √(64 / 27g^2)
Conclusion:
The maximum displacement of the ball along the x-direction for which the displacement along the y-direction is zero is √(64 / 27g^2).
To find the maximum displacement of the ball along the x-direction when the displacement along the y-direction is zero, we need to set the equation equal to zero and solve for x. Let's break down the problem step by step.
Step 1: Set the equation equal to zero.
y = x/√3 - 3gx^2/8
Since we want to find the maximum displacement of x when y is zero, we can set y equal to zero and solve for x.
0 = x/√3 - 3gx^2/8
Step 2: Simplify the equation.
To simplify the equation, we can multiply the entire equation by 8 to eliminate the fractions.
0 = 8(x/√3) - 8(3gx^2/8)
0 = 8x/√3 - 3gx^2
Step 3: Rearrange the equation.
To make the equation easier to work with, let's rearrange it.
3gx^2 = 8x/√3
Step 4: Square both sides of the equation.
To eliminate the square root, we can square both sides of the equation.
(3gx^2)^2 = (8x/√3)^2
9g^2x^4 = 64x^2/3
Step 5: Simplify the equation.
To simplify the equation, we can multiply both sides by 3 to eliminate the fraction.
27g^2x^4 = 64x^2
Step 6: Solve for x.
To solve for x, we can divide both sides of the equation by x^2.
27g^2x^2 = 64
x^2 = 64 / 27g^2
x = ±√(64 / 27g^2)
Step 7: Determine the maximum displacement.
Since we are looking for the maximum displacement along the x-direction, we only consider the positive value of x.
Therefore, the maximum displacement of the ball along the x-direction for which the displacement along the y-direction is zero is given by:
x = √(64 / 27g^2)
Conclusion:
The maximum displacement of the ball along the x-direction for which the displacement along the y-direction is zero is √(64 / 27g^2).
Community Answer
a ball thrown in air follows a path given by y=x/√3-3gx^2/8 met. where...
8✓3/45
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
a ball thrown in air follows a path given by y=x/√3-3gx^2/8 met. where xaxis is taken along the horizontal and yaxis long the vertical . the maximum displacement of the ball along x direction for which displacement along y is zero
Question Description
a ball thrown in air follows a path given by y=x/√3-3gx^2/8 met. where xaxis is taken along the horizontal and yaxis long the vertical . the maximum displacement of the ball along x direction for which displacement along y is zero for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about a ball thrown in air follows a path given by y=x/√3-3gx^2/8 met. where xaxis is taken along the horizontal and yaxis long the vertical . the maximum displacement of the ball along x direction for which displacement along y is zero covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for a ball thrown in air follows a path given by y=x/√3-3gx^2/8 met. where xaxis is taken along the horizontal and yaxis long the vertical . the maximum displacement of the ball along x direction for which displacement along y is zero.
a ball thrown in air follows a path given by y=x/√3-3gx^2/8 met. where xaxis is taken along the horizontal and yaxis long the vertical . the maximum displacement of the ball along x direction for which displacement along y is zero for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about a ball thrown in air follows a path given by y=x/√3-3gx^2/8 met. where xaxis is taken along the horizontal and yaxis long the vertical . the maximum displacement of the ball along x direction for which displacement along y is zero covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for a ball thrown in air follows a path given by y=x/√3-3gx^2/8 met. where xaxis is taken along the horizontal and yaxis long the vertical . the maximum displacement of the ball along x direction for which displacement along y is zero.
Solutions for a ball thrown in air follows a path given by y=x/√3-3gx^2/8 met. where xaxis is taken along the horizontal and yaxis long the vertical . the maximum displacement of the ball along x direction for which displacement along y is zero in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of a ball thrown in air follows a path given by y=x/√3-3gx^2/8 met. where xaxis is taken along the horizontal and yaxis long the vertical . the maximum displacement of the ball along x direction for which displacement along y is zero defined & explained in the simplest way possible. Besides giving the explanation of
a ball thrown in air follows a path given by y=x/√3-3gx^2/8 met. where xaxis is taken along the horizontal and yaxis long the vertical . the maximum displacement of the ball along x direction for which displacement along y is zero, a detailed solution for a ball thrown in air follows a path given by y=x/√3-3gx^2/8 met. where xaxis is taken along the horizontal and yaxis long the vertical . the maximum displacement of the ball along x direction for which displacement along y is zero has been provided alongside types of a ball thrown in air follows a path given by y=x/√3-3gx^2/8 met. where xaxis is taken along the horizontal and yaxis long the vertical . the maximum displacement of the ball along x direction for which displacement along y is zero theory, EduRev gives you an
ample number of questions to practice a ball thrown in air follows a path given by y=x/√3-3gx^2/8 met. where xaxis is taken along the horizontal and yaxis long the vertical . the maximum displacement of the ball along x direction for which displacement along y is zero tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup