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In an experiment of photoelectric emission for incident light of 4000 A0, the stopping potential is 2V. If the wavelength of incident light is made 3000 A0, then stopping potential will be
- a)zero
- b)more than 2 volt
- c)2 Volt
- d)less than 2 volt
Correct answer is option 'B'. Can you explain this answer?
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In an experiment of photoelectric emission for incident light of 4000A...
The maximum kinetic energy for the photoelectrons is
Emax=hν−ϕ
where, ν is the frequency of incident light and ϕ is photoelectric work function of metal.
If Vo is the stopping potential then
eV0=h(c/λ)−ϕ .....................(since, ν=c/λ)
As per the problem, for incident light of 4000Ao, the stopping potential is 2V. When the wavelength of incident light is reduced to 3000Ao, then the stopping potential will increase to value more than 2V(as per the above equation).
Emax=hν−ϕ
where, ν is the frequency of incident light and ϕ is photoelectric work function of metal.
If Vo is the stopping potential then
eV0=h(c/λ)−ϕ .....................(since, ν=c/λ)
As per the problem, for incident light of 4000Ao, the stopping potential is 2V. When the wavelength of incident light is reduced to 3000Ao, then the stopping potential will increase to value more than 2V(as per the above equation).
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In an experiment of photoelectric emission for incident light of 4000A...
The maximum kinetic energy for the photoelectrons is
Emax=hν−ϕ
where, ν is the frequency of incident light and ϕ is photoelectric work function of metal.
If Vo is the stopping potential then
eV0=h(c/λ)−ϕ .....................(since, ν=c/λ)
As per the problem, for incident light of 4000Ao, the stopping potential is 2V. When the wavelength of incident light is reduced to 3000Ao, then the stopping potential will increase to value more than 2V(as per the above equation).
Emax=hν−ϕ
where, ν is the frequency of incident light and ϕ is photoelectric work function of metal.
If Vo is the stopping potential then
eV0=h(c/λ)−ϕ .....................(since, ν=c/λ)
As per the problem, for incident light of 4000Ao, the stopping potential is 2V. When the wavelength of incident light is reduced to 3000Ao, then the stopping potential will increase to value more than 2V(as per the above equation).
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In an experiment of photoelectric emission for incident light of 4000A0, the stopping potential is 2V. If the wavelength of incident light is made 3000A0, then stopping potential will bea)zerob)more than 2 voltc)2 Voltd)less than 2 voltCorrect answer is option 'B'. Can you explain this answer?
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In an experiment of photoelectric emission for incident light of 4000A0, the stopping potential is 2V. If the wavelength of incident light is made 3000A0, then stopping potential will bea)zerob)more than 2 voltc)2 Voltd)less than 2 voltCorrect answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about In an experiment of photoelectric emission for incident light of 4000A0, the stopping potential is 2V. If the wavelength of incident light is made 3000A0, then stopping potential will bea)zerob)more than 2 voltc)2 Voltd)less than 2 voltCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In an experiment of photoelectric emission for incident light of 4000A0, the stopping potential is 2V. If the wavelength of incident light is made 3000A0, then stopping potential will bea)zerob)more than 2 voltc)2 Voltd)less than 2 voltCorrect answer is option 'B'. Can you explain this answer?.
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