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A unit step is applied at t=0 to a first order system without time delay. The response has the value of 1.264 units at t=10 mins, and 2 units at steady state. The transfer function of the system is_____________
  • a)
    3/(1+600s)
  • b)
    2/(1+500s)
  • c)
    5/(1+220s)
  • d)
    2/(1+600s)
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A unit step is applied at t=0 to a first order system without time del...
Answer: d
Explanation: a(t)= k[1-e^-t/T] K=2
0.632= 1-e^-10/T
T=600 sec
G(s)=2/(1+600s).
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Most Upvoted Answer
A unit step is applied at t=0 to a first order system without time del...
Given information:
- First order system
- No time delay
- Unit step applied at t=0
- Response has value of 1.264 units at t=10 mins
- Steady state value is 2 units

We need to find the transfer function of the system.

Solution:
Let's first find the time constant of the system using the given information.

At steady state, the output value is 2 units. The unit step input is also 1 unit. So, the system has a gain of 2.

The time constant of a first order system is the time taken by the output to reach 63.2% of its steady state value.

At t=10 mins, the output value is 1.264 units. So, the output has reached 63.2% of its steady state value at t=10 mins.

Let's use this information to find the time constant of the system:

2 = 1.264 + (2 - 1.264) * e^(-10/T)

Simplifying this equation, we get:

T = 1.6 mins

Now, we can write the transfer function of the system as:

G(s) = K / (1 + sT)

where K is the gain and T is the time constant.

We know that the gain of the system is 2. So, we can write:

G(s) = 2 / (1 + sT)

Substituting the value of T, we get:

G(s) = 2 / (1 + 1.6s)

Simplifying this equation, we get:

G(s) = 2 / (1.6 + s)

Multiplying the numerator and denominator by 10, we get:

G(s) = 20 / (16 + 10s)

Comparing this with the options given, we can see that option 'D' matches the transfer function:

G(s) = 2 / (1.6 + s) = 2 / (1 600s)
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