Introduction:
When a metallic surface is illuminated with light, electrons can be emitted from the surface. The energy required to remove an electron from the surface of a metal is known as the work function of the metal. In this case, we are given the wavelength of the incident light and the maximum energy of the emitted electrons. We can use these values to calculate the work function of the metal.

Formula:
The energy of a photon can be calculated using the equation:
E = hc/λ
where E is the energy of the photon, h is the Planck's constant (6.626 x 10^-34 J.s), c is the speed of light (3 x 10^8 m/s), and λ is the wavelength of the light.

Calculating the energy of the incident light:
Using the given wavelength of 3333 amestrong unit (3.333 x 10^-10 m), we can calculate the energy of the incident light using the above formula:
E = (6.626 x 10^-34 J.s * 3 x 10^8 m/s) / (3.333 x 10^-10 m)
E ≈ 1.99 x 10^-19 J

Calculating the work function:
The maximum energy of the emitted electrons is given as 0.6 eV. To convert this to joules, we can use the conversion factor:
1 eV = 1.6 x 10^-19 J

So, the maximum energy of the emitted electrons can be written as:
0.6 eV = 0.6 * 1.6 x 10^-19 J = 9.6 x 10^-20 J

The work function (Φ) can be calculated by subtracting the energy of the incident light from the maximum energy of the emitted electrons:
Φ = 9.6 x 10^-20 J - 1.99 x 10^-19 J
Φ ≈ -1.03 x 10^-19 J

Explanation:
The negative sign in the result indicates that the work function is greater than the energy of the incident light. This means that the electrons are not emitted with enough energy to overcome the work function and are therefore not emitted from the metal surface.

Conclusion:
The work function of the metal is approximately -1.03 x 10^-19 J.

Hi azar use the basic plancks formula i.e hv=work function+K.E