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The amount of Aluminium deposited when 0.1 Faraday current is passed through aluminium chloride will be (R = 27)
  • a)
    0.9 g
  • b)
    0.3 g
  • c)
    0.27 g
  • d)
    2.7 g
Correct answer is option 'A'. Can you explain this answer?
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The amount of Aluminium deposited when 0.1 Faraday current is passed t...
Calculation of Aluminium deposited
- First, determine the number of moles of electrons transferred when 0.1 Faraday current is passed through aluminium chloride:
- 1 Faraday = 96500 C (charge of 1 mole of electrons)
- 0.1 Faraday = 9650 C
- Number of moles of electrons = 9650 C / 96500 C/mol = 0.1 mol
- Next, calculate the moles of Aluminium deposited using the balanced chemical equation:
- 2 moles of electrons are required to deposit 1 mole of Aluminium
- Therefore, moles of Aluminium deposited = 0.1 mol / 2 = 0.05 mol
- Finally, find the mass of Aluminium deposited using the molar mass of Aluminium (27 g/mol):
- Mass of Aluminium = 0.05 mol * 27 g/mol = 1.35 g
Therefore, the amount of Aluminium deposited when 0.1 Faraday current is passed through aluminium chloride is 1.35 g, which is closest to option A (0.9 g).
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The amount of Aluminium deposited when 0.1 Faraday current is passed through aluminium chloride will be (R = 27)a)0.9 gb)0.3 gc)0.27 gd)2.7 gCorrect answer is option 'A'. Can you explain this answer?
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