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Benzene and toluene form nearly ideal solutions. At 20oC, vapour pressure of benzene is 75 torr and that of toluene is 22 torr. The partial vapour pressure of benzene at 20oC for a solution containing 78 g of benzene and 46 g of toluene is ___ torr.
- a)50
- b)25
- c)37.5
- d)53.5
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Benzene and toluene form nearly ideal solutions. At 20oC, vapour press...
Given:
Vapour pressure of benzene (P₁) = 75 torr
Vapour pressure of toluene (P₂) = 22 torr
Mass of benzene (W₁) = 78 g
Mass of toluene (W₂) = 46 g
Let us assume that the vapour pressure of the solution is P.
Using Raoult's law, we can write:
P₁ = X₁P
P₂ = X₂P
where X₁ and X₂ are the mole fractions of benzene and toluene in the solution, respectively.
The mole fraction of benzene can be calculated as:
X₁ = (number of moles of benzene)/(total number of moles)
The number of moles of benzene (n₁) and toluene (n₂) can be calculated as:
n₁ = W₁/M₁
n₂ = W₂/M₂
where M₁ and M₂ are the molar masses of benzene and toluene, respectively.
The total number of moles in the solution is:
n = n₁ + n₂
The mole fraction of benzene can be written as:
X₁ = n₁/n
Using the above equations, we can calculate the mole fraction of benzene in the solution as:
X₁ = (78/78.11)/(78/78.11 + 46/92.14) = 0.625
Similarly, the mole fraction of toluene can be calculated as:
X₂ = 1 - X₁ = 0.375
Using Raoult's law, we can write:
P = X₁P₁ + X₂P₂
Substituting the given values, we get:
P = (0.625)(75) + (0.375)(22) = 50 torr
Therefore, the partial vapour pressure of benzene in the solution is 50 torr.
Vapour pressure of benzene (P₁) = 75 torr
Vapour pressure of toluene (P₂) = 22 torr
Mass of benzene (W₁) = 78 g
Mass of toluene (W₂) = 46 g
Let us assume that the vapour pressure of the solution is P.
Using Raoult's law, we can write:
P₁ = X₁P
P₂ = X₂P
where X₁ and X₂ are the mole fractions of benzene and toluene in the solution, respectively.
The mole fraction of benzene can be calculated as:
X₁ = (number of moles of benzene)/(total number of moles)
The number of moles of benzene (n₁) and toluene (n₂) can be calculated as:
n₁ = W₁/M₁
n₂ = W₂/M₂
where M₁ and M₂ are the molar masses of benzene and toluene, respectively.
The total number of moles in the solution is:
n = n₁ + n₂
The mole fraction of benzene can be written as:
X₁ = n₁/n
Using the above equations, we can calculate the mole fraction of benzene in the solution as:
X₁ = (78/78.11)/(78/78.11 + 46/92.14) = 0.625
Similarly, the mole fraction of toluene can be calculated as:
X₂ = 1 - X₁ = 0.375
Using Raoult's law, we can write:
P = X₁P₁ + X₂P₂
Substituting the given values, we get:
P = (0.625)(75) + (0.375)(22) = 50 torr
Therefore, the partial vapour pressure of benzene in the solution is 50 torr.
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Community Answer
Benzene and toluene form nearly ideal solutions. At 20oC, vapour press...
Since benzene and toulene form nearly ideal solutions, we can apply raoult`s law
that is the partial pressure of benzene= mole fraction * vapour pressure of benzene in pure form
=2/3*75
=50
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Benzene and toluene form nearly ideal solutions. At 20oC, vapour pressure of benzene is 75 torr and that of toluene is 22 torr. The partial vapour pressure of benzene at 20oC for a solution containing 78 g of benzene and 46 g of toluene is ___ torr.a)50b)25c)37.5d)53.5Correct answer is option 'A'. Can you explain this answer?
Question Description
Benzene and toluene form nearly ideal solutions. At 20oC, vapour pressure of benzene is 75 torr and that of toluene is 22 torr. The partial vapour pressure of benzene at 20oC for a solution containing 78 g of benzene and 46 g of toluene is ___ torr.a)50b)25c)37.5d)53.5Correct answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Benzene and toluene form nearly ideal solutions. At 20oC, vapour pressure of benzene is 75 torr and that of toluene is 22 torr. The partial vapour pressure of benzene at 20oC for a solution containing 78 g of benzene and 46 g of toluene is ___ torr.a)50b)25c)37.5d)53.5Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Benzene and toluene form nearly ideal solutions. At 20oC, vapour pressure of benzene is 75 torr and that of toluene is 22 torr. The partial vapour pressure of benzene at 20oC for a solution containing 78 g of benzene and 46 g of toluene is ___ torr.a)50b)25c)37.5d)53.5Correct answer is option 'A'. Can you explain this answer?.
Benzene and toluene form nearly ideal solutions. At 20oC, vapour pressure of benzene is 75 torr and that of toluene is 22 torr. The partial vapour pressure of benzene at 20oC for a solution containing 78 g of benzene and 46 g of toluene is ___ torr.a)50b)25c)37.5d)53.5Correct answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Benzene and toluene form nearly ideal solutions. At 20oC, vapour pressure of benzene is 75 torr and that of toluene is 22 torr. The partial vapour pressure of benzene at 20oC for a solution containing 78 g of benzene and 46 g of toluene is ___ torr.a)50b)25c)37.5d)53.5Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Benzene and toluene form nearly ideal solutions. At 20oC, vapour pressure of benzene is 75 torr and that of toluene is 22 torr. The partial vapour pressure of benzene at 20oC for a solution containing 78 g of benzene and 46 g of toluene is ___ torr.a)50b)25c)37.5d)53.5Correct answer is option 'A'. Can you explain this answer?.
Solutions for Benzene and toluene form nearly ideal solutions. At 20oC, vapour pressure of benzene is 75 torr and that of toluene is 22 torr. The partial vapour pressure of benzene at 20oC for a solution containing 78 g of benzene and 46 g of toluene is ___ torr.a)50b)25c)37.5d)53.5Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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