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For the complete oxidation of 100 g of Cyclohexanol to cyclohexanon, the quantity of CrO3 required is (assuming 100% chemical yield) [Atomic wt. of Cr = 52)
- a)50 grams
- b)67 grams
- c)133 grams
- d)100 grams.
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
For the complete oxidation of 100 g of Cyclohexanol to cyclohexanon, t...
As we know that, Cr = 52,
O3 = 16*3 = 48
CrO3 = 52 = 48
= 100 gm
O3 = 16*3 = 48
CrO3 = 52 = 48
= 100 gm
Most Upvoted Answer
For the complete oxidation of 100 g of Cyclohexanol to cyclohexanon, t...
Calculation of CrO3 required for the oxidation of Cyclohexanol to Cyclohexanon
Given:
- Mass of Cyclohexanol = 100 g
- 100% chemical yield is assumed
- Atomic weight of Cr = 52
Step 1: Write the balanced chemical equation for the oxidation reaction
Cyclohexanol + CrO3 → Cyclohexanone + Cr2O3 + H2O
Step 2: Determine the molar mass of Cyclohexanol and CrO3
- Molar mass of Cyclohexanol = 6(12.01) + 11(1.01) + 1(16.00) = 100.16 g/mol
- Molar mass of CrO3 = 52 + 3(16) = 100 g/mol
Step 3: Convert the mass of Cyclohexanol to the number of moles
- Number of moles of Cyclohexanol = 100 g / 100.16 g/mol = 0.998 mol
Step 4: Use the stoichiometric ratio to determine the number of moles of CrO3 required
- From the balanced equation, it can be seen that 1 mole of Cyclohexanol reacts with 1 mole of CrO3
- Therefore, the number of moles of CrO3 required = 0.998 mol
Step 5: Convert the number of moles of CrO3 to mass
- Mass of CrO3 required = number of moles x molar mass = 0.998 mol x 100 g/mol = 99.8 g
- Rounding off to one significant figure, the mass of CrO3 required is 100 g.
Therefore, the quantity of CrO3 required for the complete oxidation of 100 g of Cyclohexanol to Cyclohexanon is 100 grams.
Given:
- Mass of Cyclohexanol = 100 g
- 100% chemical yield is assumed
- Atomic weight of Cr = 52
Step 1: Write the balanced chemical equation for the oxidation reaction
Cyclohexanol + CrO3 → Cyclohexanone + Cr2O3 + H2O
Step 2: Determine the molar mass of Cyclohexanol and CrO3
- Molar mass of Cyclohexanol = 6(12.01) + 11(1.01) + 1(16.00) = 100.16 g/mol
- Molar mass of CrO3 = 52 + 3(16) = 100 g/mol
Step 3: Convert the mass of Cyclohexanol to the number of moles
- Number of moles of Cyclohexanol = 100 g / 100.16 g/mol = 0.998 mol
Step 4: Use the stoichiometric ratio to determine the number of moles of CrO3 required
- From the balanced equation, it can be seen that 1 mole of Cyclohexanol reacts with 1 mole of CrO3
- Therefore, the number of moles of CrO3 required = 0.998 mol
Step 5: Convert the number of moles of CrO3 to mass
- Mass of CrO3 required = number of moles x molar mass = 0.998 mol x 100 g/mol = 99.8 g
- Rounding off to one significant figure, the mass of CrO3 required is 100 g.
Therefore, the quantity of CrO3 required for the complete oxidation of 100 g of Cyclohexanol to Cyclohexanon is 100 grams.
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Community Answer
For the complete oxidation of 100 g of Cyclohexanol to cyclohexanon, t...
D)100 gm
1 mole cyclohexanol + 1 mole CrO3 = 1 mole cyhxnon
100 gm. 100 gm.
i.e., 100 gm of CrO3 is required to oxidise 100 gm of cyclohexanol
Cr= 52 O3= 16×3=48
so, CrO3 = 100 gm
1 mole cyclohexanol + 1 mole CrO3 = 1 mole cyhxnon
100 gm. 100 gm.
i.e., 100 gm of CrO3 is required to oxidise 100 gm of cyclohexanol
Cr= 52 O3= 16×3=48
so, CrO3 = 100 gm
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For the complete oxidation of 100 g of Cyclohexanol to cyclohexanon, the quantity of CrO3 required is (assuming 100% chemical yield) [Atomic wt. of Cr = 52)a)50 gramsb)67 gramsc)133 gramsd)100 grams.Correct answer is option 'D'. Can you explain this answer?
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For the complete oxidation of 100 g of Cyclohexanol to cyclohexanon, the quantity of CrO3 required is (assuming 100% chemical yield) [Atomic wt. of Cr = 52)a)50 gramsb)67 gramsc)133 gramsd)100 grams.Correct answer is option 'D'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about For the complete oxidation of 100 g of Cyclohexanol to cyclohexanon, the quantity of CrO3 required is (assuming 100% chemical yield) [Atomic wt. of Cr = 52)a)50 gramsb)67 gramsc)133 gramsd)100 grams.Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For the complete oxidation of 100 g of Cyclohexanol to cyclohexanon, the quantity of CrO3 required is (assuming 100% chemical yield) [Atomic wt. of Cr = 52)a)50 gramsb)67 gramsc)133 gramsd)100 grams.Correct answer is option 'D'. Can you explain this answer?.
For the complete oxidation of 100 g of Cyclohexanol to cyclohexanon, the quantity of CrO3 required is (assuming 100% chemical yield) [Atomic wt. of Cr = 52)a)50 gramsb)67 gramsc)133 gramsd)100 grams.Correct answer is option 'D'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about For the complete oxidation of 100 g of Cyclohexanol to cyclohexanon, the quantity of CrO3 required is (assuming 100% chemical yield) [Atomic wt. of Cr = 52)a)50 gramsb)67 gramsc)133 gramsd)100 grams.Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For the complete oxidation of 100 g of Cyclohexanol to cyclohexanon, the quantity of CrO3 required is (assuming 100% chemical yield) [Atomic wt. of Cr = 52)a)50 gramsb)67 gramsc)133 gramsd)100 grams.Correct answer is option 'D'. Can you explain this answer?.
Solutions for For the complete oxidation of 100 g of Cyclohexanol to cyclohexanon, the quantity of CrO3 required is (assuming 100% chemical yield) [Atomic wt. of Cr = 52)a)50 gramsb)67 gramsc)133 gramsd)100 grams.Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry.
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For the complete oxidation of 100 g of Cyclohexanol to cyclohexanon, the quantity of CrO3 required is (assuming 100% chemical yield) [Atomic wt. of Cr = 52)a)50 gramsb)67 gramsc)133 gramsd)100 grams.Correct answer is option 'D'. Can you explain this answer?, a detailed solution for For the complete oxidation of 100 g of Cyclohexanol to cyclohexanon, the quantity of CrO3 required is (assuming 100% chemical yield) [Atomic wt. of Cr = 52)a)50 gramsb)67 gramsc)133 gramsd)100 grams.Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of For the complete oxidation of 100 g of Cyclohexanol to cyclohexanon, the quantity of CrO3 required is (assuming 100% chemical yield) [Atomic wt. of Cr = 52)a)50 gramsb)67 gramsc)133 gramsd)100 grams.Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
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