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The product of minimum value of xx and maximum value of  is
  • a)
    e
  • b)
     e_1
  • c)
    1
  • d)
     e2
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The product of minimum value of xxand maximum value ofisa)eb)e_1c)1d)e...
f(x) = xx     f(x) = x(-x)
f’(x) = xx(1+ln x)          f’(x) = -x(-x)(1+ln x)
1+ln x = 0                   x = 1/e
x = 1/e
Min value = (1/e)(1/e)        f(1/e) = e(1/e)
Product = (e-1/e)(e)1/e = 1
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