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The minimum value of the function defined by f(x) = max (x, x + 1, 2 – x) is
- a)0
- b)1/2
- c)1
- d)3/2
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
The minimum value of the function defined by f(x) = max (x, x + 1, 2 &...
Bhai dekh iss func ka graph bana ....mtlb ki f(x) = x, f(x) = x+ 1 aur f(x) = 2 - x , ye teeno func ek hi graph pe.now see, jo f(x) = x aur f(x) = x+1 hai woh to kahi bhi intersect nhi krege qki dono ||ᵉˡ line hai..aur jab tu f(x) = 2 - x ka graph banaega to inn dono ko intersect karte hue jyega.ab jo top most intersection point wohi sbse tagda hoga aur wohi f(x) = max. {x, x + 1, 2 - x} ki value hogi...so, f(x) = x + 1 and f(x) = 2 - x ka intersection iss graph ka top point hai ... to isko solve krke x = 1/2 aa rha hai aur iss x ki value ko f(x) me put krde to uski value 3/2 aayegi...and according to ques the value of f(x) = max. {x, x + 1, 2 - x} is the minimum value of function.i hope u will understand....
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Community Answer
The minimum value of the function defined by f(x) = max (x, x + 1, 2 &...
f(x) = max(x, x+1, 2-x)
y = 2-x
y = x+1
Comparing both the equations, we get
2 - x = x + 1
x = ½
y = 2 - x
y = 2 - (½)
y = 1/3
y = 2-x
y = x+1
Comparing both the equations, we get
2 - x = x + 1
x = ½
y = 2 - x
y = 2 - (½)
y = 1/3
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The minimum value of the function defined by f(x) = max (x, x + 1, 2 –x) isa)0b)1/2c)1d)3/2Correct answer is option 'D'. Can you explain this answer?
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The minimum value of the function defined by f(x) = max (x, x + 1, 2 –x) isa)0b)1/2c)1d)3/2Correct answer is option 'D'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The minimum value of the function defined by f(x) = max (x, x + 1, 2 –x) isa)0b)1/2c)1d)3/2Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The minimum value of the function defined by f(x) = max (x, x + 1, 2 –x) isa)0b)1/2c)1d)3/2Correct answer is option 'D'. Can you explain this answer?.
The minimum value of the function defined by f(x) = max (x, x + 1, 2 –x) isa)0b)1/2c)1d)3/2Correct answer is option 'D'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The minimum value of the function defined by f(x) = max (x, x + 1, 2 –x) isa)0b)1/2c)1d)3/2Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The minimum value of the function defined by f(x) = max (x, x + 1, 2 –x) isa)0b)1/2c)1d)3/2Correct answer is option 'D'. Can you explain this answer?.
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