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How many time can a 6 kb fragment be present in 3.9 micrograms of DNA containing 6 billion bases? Assume the MW of one bp to be 650 Da.
  • a)
    1
  • b)
    100
  • c)
    600,000
  • d)
    100 million
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
How many time can a 6 kb fragment be present in 3.9 micrograms of DNA ...
To find out how many times a 6 kb fragment can be present in 3.9 micrograms of DNA containing 6 billion bases, we need to calculate the number of fragments that can be formed and then divide it by the size of the fragment.

1. Calculate the number of bases in 3.9 micrograms of DNA:
- Given: 1 microgram = 1 × 10^6 grams
- The molecular weight of DNA is approximately 650 Da per base pair.
- Therefore, the number of bases in 3.9 micrograms of DNA is:
Number of bases = (3.9 × 10^-6 grams) / (650 Da/base) = 6 × 10^9 bases

2. Calculate the number of fragments that can be formed:
- The size of the fragment is given as 6 kb, which means 6,000 base pairs.
- Divide the total number of bases by the size of the fragment:
Number of fragments = (6 × 10^9 bases) / (6,000 bases/fragment) = 1 × 10^6 fragments

3. Calculate the number of times the 6 kb fragment is present:
- Divide the number of fragments by 1, as each fragment is 6 kb in size:
Number of times the 6 kb fragment is present = 1 × 10^6 fragments / 1 = 1 × 10^6

Hence, the correct answer is option 'B' - 100.
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