A bullet hits and gets embedded in a solid block resting on frictionle...
Momentum and Kinetic Energy in the Process of a Bullet Hitting and Embedding in a Solid Block on a Frictionless Surface
Introduction:
When a bullet hits and embeds itself in a solid block resting on a frictionless surface, there are certain physical quantities that are conserved in the process. The two most important quantities to consider in this scenario are momentum and kinetic energy.
Explanation:
1. Momentum Conservation:
Momentum is defined as the product of an object's mass and velocity. In this scenario, both the bullet and the block have momentum before and after the collision. According to the law of conservation of momentum, the total momentum of an isolated system remains constant if no external forces act on it. Since there are no external forces acting on the system in this case, the total momentum of the bullet and the block will be conserved.
2. Kinetic Energy:
Kinetic energy is the energy possessed by an object due to its motion. In this scenario, the bullet has kinetic energy before the collision, which is transferred to the block upon embedding. However, after the collision, the block and the embedded bullet have a common velocity, and the bullet no longer possesses kinetic energy. Therefore, the kinetic energy is not conserved in this process.
Conclusion:
Based on the explanation above, the correct answer is option 'A' - Only momentum is conserved. While momentum is conserved in this scenario, kinetic energy is not conserved as it is transformed into other forms of energy, such as potential energy or heat.
A bullet hits and gets embedded in a solid block resting on frictionle...
It's answer is 'C'.Explanation:No external force is acting on the bullet + solid block system, thus linear momentum of the system is conserved.Also is it perfectly inelastic collision, so k.E does not conserved. So, only momentum will conserved.......
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