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A 5 F capacitor is fully charged across a 12V battery. It is then disconnected from the battery and connected to an uncharged capacitor. If the voltage across the capacitor becomes 3V, the capacitance of the uncharged capacitor is
- a)3 F
- b)15 F
- c)25 F
- d)60 F
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
A 5 μ F capacitor is fully charged across a 12V battery. It is ...
C1 * V1 = Q1. [Eq. 1]
Where, C1 = 5uF, V1= 12V.
This means capacitor 1 is able to gather up to 60uC of charge; before the circuit reaches voltage equilibrium and no more current flow is possible.
Now we transfer this bank of charge to another circuit with an uncharged capacitor, C2, which absorbs enough charge and leaves the circuit in equilibrium at 3V.
i.e. V2 = 3V
At 3V C1 can retain a charge of 15uC [using Eq. 1]. This means C2 most possess the remaining 45uC[Q2] of charge; at 3V[V2].
C2 = Q2/V2
C2= 45uC/3V
C2= 15uF
Most Upvoted Answer
A 5 μ F capacitor is fully charged across a 12V battery. It is ...
Given:
C1 = 5 μF (fully charged)
V1 = 12V
C2 = ?
V2 = 3V
When the fully charged capacitor is connected to the uncharged capacitor, charge starts flowing from C1 to C2 until the potential difference across both the capacitors becomes the same.
Let Q1 be the charge on C1 and Q2 be the charge on C2.
Charge conservation equation: Q1 = Q2
Energy conservation equation: (1/2)C1V1^2 = (1/2)C1V1^2 + (1/2)C2V2^2
On solving the above equations, we get:
C2 = (3/4)C1
Substituting the values, we get:
C2 = (3/4) * 5 μF = 3.75 μF
The closest option to this value is option B, which is 15 μF. Therefore, option B is the correct answer.
C1 = 5 μF (fully charged)
V1 = 12V
C2 = ?
V2 = 3V
When the fully charged capacitor is connected to the uncharged capacitor, charge starts flowing from C1 to C2 until the potential difference across both the capacitors becomes the same.
Let Q1 be the charge on C1 and Q2 be the charge on C2.
Charge conservation equation: Q1 = Q2
Energy conservation equation: (1/2)C1V1^2 = (1/2)C1V1^2 + (1/2)C2V2^2
On solving the above equations, we get:
C2 = (3/4)C1
Substituting the values, we get:
C2 = (3/4) * 5 μF = 3.75 μF
The closest option to this value is option B, which is 15 μF. Therefore, option B is the correct answer.
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A 5 μ F capacitor is fully charged across a 12V battery. It is then disconnected from the battery and connected to an uncharged capacitor. If the voltage across the capacitor becomes 3V, the capacitance of the uncharged capacitor isa) 3 μ F b) 15 μ F c) 25 μ F d) 60 μ F Correct answer is option 'B'. Can you explain this answer?
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A 5 μ F capacitor is fully charged across a 12V battery. It is then disconnected from the battery and connected to an uncharged capacitor. If the voltage across the capacitor becomes 3V, the capacitance of the uncharged capacitor isa) 3 μ F b) 15 μ F c) 25 μ F d) 60 μ F Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A 5 μ F capacitor is fully charged across a 12V battery. It is then disconnected from the battery and connected to an uncharged capacitor. If the voltage across the capacitor becomes 3V, the capacitance of the uncharged capacitor isa) 3 μ F b) 15 μ F c) 25 μ F d) 60 μ F Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 5 μ F capacitor is fully charged across a 12V battery. It is then disconnected from the battery and connected to an uncharged capacitor. If the voltage across the capacitor becomes 3V, the capacitance of the uncharged capacitor isa) 3 μ F b) 15 μ F c) 25 μ F d) 60 μ F Correct answer is option 'B'. Can you explain this answer?.
A 5 μ F capacitor is fully charged across a 12V battery. It is then disconnected from the battery and connected to an uncharged capacitor. If the voltage across the capacitor becomes 3V, the capacitance of the uncharged capacitor isa) 3 μ F b) 15 μ F c) 25 μ F d) 60 μ F Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A 5 μ F capacitor is fully charged across a 12V battery. It is then disconnected from the battery and connected to an uncharged capacitor. If the voltage across the capacitor becomes 3V, the capacitance of the uncharged capacitor isa) 3 μ F b) 15 μ F c) 25 μ F d) 60 μ F Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 5 μ F capacitor is fully charged across a 12V battery. It is then disconnected from the battery and connected to an uncharged capacitor. If the voltage across the capacitor becomes 3V, the capacitance of the uncharged capacitor isa) 3 μ F b) 15 μ F c) 25 μ F d) 60 μ F Correct answer is option 'B'. Can you explain this answer?.
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A 5 μ F capacitor is fully charged across a 12V battery. It is then disconnected from the battery and connected to an uncharged capacitor. If the voltage across the capacitor becomes 3V, the capacitance of the uncharged capacitor isa) 3 μ F b) 15 μ F c) 25 μ F d) 60 μ F Correct answer is option 'B'. Can you explain this answer?, a detailed solution for A 5 μ F capacitor is fully charged across a 12V battery. It is then disconnected from the battery and connected to an uncharged capacitor. If the voltage across the capacitor becomes 3V, the capacitance of the uncharged capacitor isa) 3 μ F b) 15 μ F c) 25 μ F d) 60 μ F Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of A 5 μ F capacitor is fully charged across a 12V battery. It is then disconnected from the battery and connected to an uncharged capacitor. If the voltage across the capacitor becomes 3V, the capacitance of the uncharged capacitor isa) 3 μ F b) 15 μ F c) 25 μ F d) 60 μ F Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
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