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In reaction of I2 + 2S2O3→ 2I + S4O6, equivalent weight of Iodine is M/x. What is ‘x’?
    Correct answer is '2'. Can you explain this answer?
    Most Upvoted Answer
    In reaction of I2 + 2S2O3– → 2I– + S4O6–, equiv...
    The reaction between I2 and 2S2O3 is a redox reaction that produces I- ions and S4O6-2 ions. The balanced equation for the reaction is:

    I2 + 2S2O3 --> 2I- + S4O6-2

    In this reaction, I2 is reduced to I- ions, while S2O3 is oxidized to S4O6-2 ions. The I2 molecule gains two electrons to form I- ions, while the S2O3 molecule loses two electrons to form S4O6-2 ions.

    This reaction is commonly used in analytical chemistry to determine the concentration of I2 in a solution. The reaction is typically carried out in the presence of starch, which forms a deep blue complex with I2. The disappearance of the blue color indicates the completion of the reaction.

    Overall, the reaction between I2 and 2S2O3 is a redox reaction that results in the formation of I- ions and S4O6-2 ions.
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    Community Answer
    In reaction of I2 + 2S2O3– → 2I– + S4O6–, equiv...
    Nf = no. of atom participate × change of e
    nf = 2×1
    nf= 2
    yhi x hai.. x=2
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    In reaction of I2 + 2S2O3– → 2I– + S4O6–, equivalent weight of Iodine is M/x. What is ‘x’?Correct answer is '2'. Can you explain this answer?
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