Equivalent weight of H3PO4 in the above reaction is:Correct answer is '49'. Can you explain this answer?

Question

Answer

Mol wt of H3PO4 / 2 = 49

Answer

In the above reaction, two atoms of hydrogen replaced or changed their placeand converted into HPO4--....so to find out the equivalent weight, the formula is given by

Mol. wt. Of H3PO4/2 =98/2 =49

Answer

Because h3po4 gives two h+ so it's n factor is 2

Answer

Because it is clear by molecular formula
Eq weigh of H3Po4/2=weight of H3po4/2
=98/2
=49 Answer

Answer

Equivalent wt = Mol wt./valency
so here H3PO4 looses 2 H atoms so it's valency is 2.
So Equivalent wt = Mol wt of H3PO4/2
= 98/2=49.

Answer

The reaction between calcium hydroxide (Ca(OH)2) and phosphoric acid (H3PO4) is as follows:

3Ca(OH)2 + 2H3PO4 -> Ca3(PO4)2 + 6H2O

The balanced equation shows that three molecules of calcium hydroxide react with two molecules of phosphoric acid to form one molecule of calcium phosphate (Ca3(PO4)2) and six molecules of water (H2O).

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