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In a reaction, Na2S2O3 is converted to Na2S4O6. The equivalent weight of Na2S2O3 for this reaction is (mol. wt. of Na2S2O3 = M)
  • a)
    M
  • b)
    M/4
  • c)
    M/2
  • d)
    M/3
Correct answer is option 'A'. Can you explain this answer?
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In a reaction, Na2S2O3 is converted to Na2S4O6. The equivalent weight ...
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In a reaction, Na2S2O3 is converted to Na2S4O6. The equivalent weight ...
**Explanation:**

To determine the equivalent weight of Na2S2O3 for this reaction, we need to consider the stoichiometry of the reaction and the number of equivalents of Na2S2O3 involved.

The reaction given is:
Na2S2O3 → Na2S4O6

From the reaction, we can see that 1 mole of Na2S2O3 is converted to 1 mole of Na2S4O6. This means that the stoichiometric ratio between Na2S2O3 and Na2S4O6 is 1:1.

The equivalent weight is defined as the molecular weight of a substance divided by the number of equivalents of that substance involved in a chemical reaction.

Since the stoichiometric ratio between Na2S2O3 and Na2S4O6 is 1:1, it means that 1 equivalent of Na2S2O3 is involved in the reaction.

Therefore, the equivalent weight of Na2S2O3 is equal to its molecular weight (M). Hence, the correct answer is option 'A', M.
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In a reaction, Na2S2O3 is converted to Na2S4O6. The equivalent weight of Na2S2O3 for this reaction is (mol. wt. of Na2S2O3 = M)a)Mb)M/4c)M/2d)M/3Correct answer is option 'A'. Can you explain this answer?
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