A machine gun of mass 10kg fires 20 gram Bullet @ 10 Bullet per second...
For holding the gun in its position it is needed to have newtons 3rd law
hence F1=-f2 so
force needed= mA but for n bullets f=nMA so m=20/1000kg a=v/t t=1sc hence a=500
F=10×20/1000×500 Newton =100N
A machine gun of mass 10kg fires 20 gram Bullet @ 10 Bullet per second...
Mass of the machine gun: 10 kg
Mass of each bullet: 20 grams = 0.02 kg
Rate of fire: 10 bullets per second
Speed of each bullet: 500 m/s
Calculating the total momentum of the bullets:
The momentum of an object is given by the formula:
Momentum = Mass × Velocity
The momentum of each bullet can be calculated as follows:
Momentum of each bullet = Mass of bullet × Velocity of bullet = 0.02 kg × 500 m/s = 10 kg·m/s
Since the rate of fire is 10 bullets per second, the total number of bullets fired in one second is 10 bullets/s × 1 s = 10 bullets.
Therefore, the total momentum of the bullets fired in one second is:
Total momentum of bullets = Momentum of each bullet × Total number of bullets
= 10 kg·m/s × 10 bullets
= 100 kg·m/s
Calculating the force required to hold the gun in position:
The force required to hold the gun in position is equal to the change in momentum per second, according to Newton's second law of motion.
Force = Change in momentum / Time
In this case, the change in momentum per second is equal to the total momentum of the bullets fired per second, which is 100 kg·m/s.
Therefore, the force required to hold the gun in position is:
Force = 100 kg·m/s / 1 s
= 100 N
Conclusion:
The force required to hold the machine gun in position while firing 10 bullets per second, each with a speed of 500 m/s, is 100 Newtons. This force is necessary to counteract the momentum of the bullets being fired.
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