Use the formulamT = 0.29 cmK to obtain the characteristic temperature range form=5107ma)7500 Kb)7000 Kc)6000 Kd)6500 KCorrect answer is option 'C'. Can you explain this answer?

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Class 12 Exam > Class 12 Questions > Use the formulaλmT = 0.29 cmK to obtain ...

Use the formula λ_m T = 0.29 cmK to obtain the characteristic temperature range for λ_m=5×10−⁷m

a)
7500 K
b)
7000 K
c)
6000 K
d)
6500 K

Correct answer is option 'C'. Can you explain this answer?

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Use the formulaλmT = 0.29 cmK to obtain the characteristic temper...

A body at temperature T produces a continuous spectrum of wavelengths. For a black body, the wavelength corresponding to maximum intensity of radiation is given according to Planck's law by the relation, m=0.29cmK/T. For m=106m,T=2900K.Temperatures for other wavelengths can be found. These numbers tell us the temperature ranges required for obtaining radiations in different parts of the electromagnetic spectrum. Thus, to obtain visible radiation, say =5×107m, the source should have a temperature of about 6000K. A lower temperature will also produce this wavelength but not the maximum intensity.

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Use the formulaλmT = 0.29 cmK to obtain the characteristic temper...

First convert m to cm or vice-versa.
Then by taking 0.29 rounding of 0.3 simply solve it .
As T=0.3×10(7)×10(-2)×mk/5m=3×2×1000k=6000k.

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Use the formulaλmT = 0.29 cmK to obtain the characteristic temperature range forλm=5×10−7ma)7500 Kb)7000 Kc)6000 Kd)6500 KCorrect answer is option 'C'. Can you explain this answer?

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