The electrochemical cell shown below is a concentration cell.

M|M^{2+} (saturated solut ion of a sparingly so luble salt, MX_{2} || M^{2+} (0.001 mol dm^{–3})| M.

The emf of the cell depends on the difference in concentration of M^{2+} ions at the two electrodes. The emf of the cell at 298 is 0.059 V.

M|M

The emf of the cell depends on the difference in concentration of M

- a)1 × 10
^{–15} - b)4 × 10
^{–15} - c)1 × 10
^{–12} - d)4 × 10
^{–12}

Correct answer is option 'B'. Can you explain this answer?

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This discussion on The electrochemical cell shown below is a concentration cell.M|M2+ (saturated solut ion of a sparingly so luble salt, MX2 || M2+ (0.001 mol dm3)| M.The emf of the cell depends on the difference in concentration of M2+ ions at the two electrodes. The emf of the cell at 298 is 0.059 V.Q.The solubility product (Ksp ; mol3 dm9) of MX2 at 298 based on the informat ion available the given concentration cell is (take 2.303 R 298/F = 0.059 V)a)1 1015b)4 1015c)1 1012d)4 1012Correct answer is option 'B'. Can you explain this answer? is done on EduRev Study Group by Chemistry Students. The Questions and
Answers of The electrochemical cell shown below is a concentration cell.M|M2+ (saturated solut ion of a sparingly so luble salt, MX2 || M2+ (0.001 mol dm3)| M.The emf of the cell depends on the difference in concentration of M2+ ions at the two electrodes. The emf of the cell at 298 is 0.059 V.Q.The solubility product (Ksp ; mol3 dm9) of MX2 at 298 based on the informat ion available the given concentration cell is (take 2.303 R 298/F = 0.059 V)a)1 1015b)4 1015c)1 1012d)4 1012Correct answer is option 'B'. Can you explain this answer? are solved by group of students and teacher of Chemistry, which is also the largest student
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The electrochemical cell shown below is a concentration cell.M|M2+ (saturated solut ion of a sparingly so luble salt, MX2 || M2+ (0.001 mol dm3)| M.The emf of the cell depends on the difference in concentration of M2+ ions at the two electrodes. The emf of the cell at 298 is 0.059 V.Q.The solubility product (Ksp ; mol3 dm9) of MX2 at 298 based on the informat ion available the given concentration cell is (take 2.303 R 298/F = 0.059 V)a)1 1015b)4 1015c)1 1012d)4 1012Correct answer is option 'B'. Can you explain this answer? over here on EduRev! Apart from being the largest Chemistry community, EduRev has the largest solved
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