In the structure of B4O5 (OH)42-a)All four B atoms are trigonal planar...
Explanation:
The structure of B4O5(OH)42- consists of boron atoms, oxygen atoms, and hydroxide groups. The boron atoms are bonded to each other and to oxygen atoms by covalent bonds.
Two B atoms are tetrahedral: In the structure of B4O5(OH)42-, two of the boron atoms are tetrahedral. This means that each of these boron atoms is bonded to four other atoms or groups, arranged in a tetrahedral shape around the boron atom. The tetrahedral boron atoms are located at opposite corners of the molecule.
Two B atoms are trigonal planar: The other two boron atoms in the structure are trigonal planar. This means that each of these boron atoms is bonded to three other atoms or groups, arranged in a flat, triangular shape around the boron atom. The trigonal planar boron atoms are located at the remaining two corners of the molecule.
Overall structure: The structure of B4O5(OH)42- consists of a central boron atom that is surrounded by four other boron atoms, each of which is bonded to the central boron atom by a covalent bond. The boron atoms are also bonded to oxygen atoms and hydroxide groups, which form a complex network of covalent bonds throughout the molecule.
In summary, the correct answer is option D, which states that two of the boron atoms in the structure are tetrahedral and the other two are trigonal planar.