Given information:
- The body travels 2 m in the 2nd second.
- The body travels 6 m in the next 4 seconds.

To find:
- The distance traveled in the 9th second.

Explanation:
To solve this problem, we need to understand the concept of acceleration. Acceleration is the rate of change of velocity with respect to time. In this case, we are given the distance traveled in each second, but we need to find the distance traveled in the 9th second.

Step 1: Find the average velocity of the body in the first 6 seconds:
- Distance traveled in the 2nd second = 2 m
- Distance traveled in the next 4 seconds = 6 m
- Total distance traveled in the first 6 seconds = 2 m + 6 m = 8 m
- Average velocity = Total distance/Total time = 8 m / 6 s = 4/3 m/s

Step 2: Find the acceleration:
- Acceleration can be calculated using the formula: Acceleration = Change in velocity/Time taken
- Change in velocity = Final velocity - Initial velocity
- In this case, the initial velocity is 0 m/s because the body starts from rest.
- Final velocity can be calculated using the formula: Final velocity = Initial velocity + (Acceleration * Time)
- We know the average velocity in the first 6 seconds is 4/3 m/s.
- Therefore, Final velocity = 0 m/s + (Acceleration * 6 s) = 4/3 m/s
- Solving for Acceleration, we get: Acceleration = (Final velocity - Initial velocity)/Time taken = (4/3 m/s - 0 m/s) / 6 s = 2/9 m/s²

Step 3: Find the distance traveled in the 9th second:
- Velocity in the 9th second can be calculated using the formula: Velocity = Initial velocity + (Acceleration * Time)
- Initial velocity in the 9th second = 0 m/s (since it starts from rest)
- Time in the 9th second = 1 s (as each second is considered individually)
- Therefore, Velocity in the 9th second = 0 m/s + (2/9 m/s² * 1 s) = 2/9 m/s

Step 4: Calculate the distance:
- Distance traveled in the 9th second can be calculated using the formula: Distance = Initial velocity * Time + (1/2 * Acceleration * Time²)
- Initial velocity in the 9th second = 0 m/s
- Time in the 9th second = 1 s
- Acceleration = 2/9 m/s²
- Therefore, Distance traveled in the 9th second = 0 m/s * 1 s + (1/2 * 2/9 m/s² * (1 s)²) = 1/9 m

Conclusion:
The distance traveled in the 9th second is 1/9 m.