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The equation of a line passing through the intersection of lines 3x-2y-1=0 and x-4y+3=0 and point (π,0) is
  • a)
    x-y=π(1-y)
  • b)
    x-y=π(y-1)
  • c)
    x+y=π(1-y)
  • d)
    x+y=π(y+1)
Correct answer is option 'A'. Can you explain this answer?
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The equation of a line passing through the intersection of lines 3x-2y-1=0 and x-4y+3=0 and point (π,0) isa)x-y=π(1-y)b)x-y=π(y-1)c)x+y=π(1-y)d)x+y=π(y+1)Correct answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The equation of a line passing through the intersection of lines 3x-2y-1=0 and x-4y+3=0 and point (π,0) isa)x-y=π(1-y)b)x-y=π(y-1)c)x+y=π(1-y)d)x+y=π(y+1)Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The equation of a line passing through the intersection of lines 3x-2y-1=0 and x-4y+3=0 and point (π,0) isa)x-y=π(1-y)b)x-y=π(y-1)c)x+y=π(1-y)d)x+y=π(y+1)Correct answer is option 'A'. Can you explain this answer?.
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