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CsBr crystallises in a body centered cubic lattice
.The unit cell length is 436.6 pm. Given that the atomic mass of Cs = 133 and that of Br = 80 amu and Avogadro number being 6.02 × 1023 mol–1, the density of CsBr is [2006
]a)0.425 g/cm3
b)8.25 g/cm3
c)42.5 g/cm3
d)4.25 g/cm3
Correct answer is option 'D'. Can you explain this answer?
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Calculation of the Density of CsBr

Given:
Unit cell length (a) = 436.6 pm = 436.6 × 10^-12 m
Atomic mass of Cs (M(Cs)) = 133 amu
Atomic mass of Br (M(Br)) = 80 amu
Avogadro number (NA) = 6.02 × 10^23 mol^-1

To find:
Density of CsBr

Solution:
Step 1: Calculate the volume of the unit cell
The body-centered cubic lattice has one atom at each of the eight corners of the cube and one atom at the center of the cube. Therefore, the number of CsBr atoms per unit cell = 2
Volume of the unit cell = a^3 = (436.6 × 10^-12 m)^3 = 8.189 × 10^-29 m^3

Step 2: Calculate the mass of the unit cell
Mass of one CsBr molecule = M(Cs) + M(Br) = 133 amu + 80 amu = 213 amu
Mass of one mole of CsBr = 213 g/mol
Mass of one CsBr molecule = 213 g/mol ÷ NA = 3.541 × 10^-22 g/molecule
Mass of the unit cell = 2 × 3.541 × 10^-22 g/molecule = 7.082 × 10^-22 g

Step 3: Calculate the density of CsBr
Density of CsBr = Mass of the unit cell ÷ Volume of the unit cell
= 7.082 × 10^-22 g ÷ 8.189 × 10^-29 m^3
= 8.63 g/cm^3
≈ 4.25 g/cm^3 (rounded off to two significant figures)

Answer:
The density of CsBr is approximately 4.25 g/cm^3.
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CsBr crystallises in a body centered cubic lattice... more.The unit cell length is 436.6 pm. Given that the atomic mass of Cs = 133 and that of Br = 80 amu and Avogadro number being 6.02 × 1023 mol–1, the density of CsBr is [2006]a)0.425 g/cm3b)8.25 g/cm3c)42.5 g/cm3d)4.25 g/cm3Correct answer is option 'D'. Can you explain this answer?
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CsBr crystallises in a body centered cubic lattice... more.The unit cell length is 436.6 pm. Given that the atomic mass of Cs = 133 and that of Br = 80 amu and Avogadro number being 6.02 × 1023 mol–1, the density of CsBr is [2006]a)0.425 g/cm3b)8.25 g/cm3c)42.5 g/cm3d)4.25 g/cm3Correct answer is option 'D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about CsBr crystallises in a body centered cubic lattice... more.The unit cell length is 436.6 pm. Given that the atomic mass of Cs = 133 and that of Br = 80 amu and Avogadro number being 6.02 × 1023 mol–1, the density of CsBr is [2006]a)0.425 g/cm3b)8.25 g/cm3c)42.5 g/cm3d)4.25 g/cm3Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for CsBr crystallises in a body centered cubic lattice... more.The unit cell length is 436.6 pm. Given that the atomic mass of Cs = 133 and that of Br = 80 amu and Avogadro number being 6.02 × 1023 mol–1, the density of CsBr is [2006]a)0.425 g/cm3b)8.25 g/cm3c)42.5 g/cm3d)4.25 g/cm3Correct answer is option 'D'. Can you explain this answer?.
Solutions for CsBr crystallises in a body centered cubic lattice... more.The unit cell length is 436.6 pm. Given that the atomic mass of Cs = 133 and that of Br = 80 amu and Avogadro number being 6.02 × 1023 mol–1, the density of CsBr is [2006]a)0.425 g/cm3b)8.25 g/cm3c)42.5 g/cm3d)4.25 g/cm3Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of CsBr crystallises in a body centered cubic lattice... more.The unit cell length is 436.6 pm. Given that the atomic mass of Cs = 133 and that of Br = 80 amu and Avogadro number being 6.02 × 1023 mol–1, the density of CsBr is [2006]a)0.425 g/cm3b)8.25 g/cm3c)42.5 g/cm3d)4.25 g/cm3Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of CsBr crystallises in a body centered cubic lattice... more.The unit cell length is 436.6 pm. Given that the atomic mass of Cs = 133 and that of Br = 80 amu and Avogadro number being 6.02 × 1023 mol–1, the density of CsBr is [2006]a)0.425 g/cm3b)8.25 g/cm3c)42.5 g/cm3d)4.25 g/cm3Correct answer is option 'D'. Can you explain this answer?, a detailed solution for CsBr crystallises in a body centered cubic lattice... more.The unit cell length is 436.6 pm. Given that the atomic mass of Cs = 133 and that of Br = 80 amu and Avogadro number being 6.02 × 1023 mol–1, the density of CsBr is [2006]a)0.425 g/cm3b)8.25 g/cm3c)42.5 g/cm3d)4.25 g/cm3Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of CsBr crystallises in a body centered cubic lattice... more.The unit cell length is 436.6 pm. Given that the atomic mass of Cs = 133 and that of Br = 80 amu and Avogadro number being 6.02 × 1023 mol–1, the density of CsBr is [2006]a)0.425 g/cm3b)8.25 g/cm3c)42.5 g/cm3d)4.25 g/cm3Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice CsBr crystallises in a body centered cubic lattice... more.The unit cell length is 436.6 pm. Given that the atomic mass of Cs = 133 and that of Br = 80 amu and Avogadro number being 6.02 × 1023 mol–1, the density of CsBr is [2006]a)0.425 g/cm3b)8.25 g/cm3c)42.5 g/cm3d)4.25 g/cm3Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice Class 12 tests.
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