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A pump delivers water at a rate of 0.025 m3/s against a head of 30 m. If the overall efficiency of the pump is 75%, the power required by the pump is:
  • a)
    1 kW
  • b)
    4.9 kW
  • c)
    7.8 kW
  • d)
    9.8 kW
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A pump delivers water at a rate of 0.025 m3/s against a head of 30 m. ...
Power required:
 
 
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Most Upvoted Answer
A pump delivers water at a rate of 0.025 m3/s against a head of 30 m. ...
Given:
Rate of water delivered (Q) = 0.025 m³/s
Head (H) = 30 m
Overall efficiency (η) = 75%

To find: Power required by the pump (P)

Formula used:
Power (P) = (Q × H × ρ × g) / η
Where,
ρ = Density of water = 1000 kg/m³
g = Acceleration due to gravity = 9.81 m/s²

Calculation:
Substituting the given values in the formula, we get:
P = (0.025 × 30 × 1000 × 9.81) / 0.75
P = 9.8 kW

Therefore, the power required by the pump is 9.8 kW.
Hence, the correct option is (D).
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