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In the preparation of P4O6, a mixture of N2 and oxygen is used instead of pure oxygen. The reason is:
- a)Pure oxygen will form ozone in presence of P.
- b)Pure oxygen will form P4O10 despite excess of P4, in pure oxygen.
- c)Pure oxygen will form [P(O3)4] ozonide.
- d)Pure oxygen will not react with P. N2 acts as a catalyst.
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
In the preparation of P4O6, a mixture of N2 and oxygen is used instead...
Explanation:
Preparation of P4O6 requires the reaction of phosphorus with oxygen. However, in the presence of excess oxygen, P4O10 is formed instead of P4O6. To prevent this, a mixture of N2 and oxygen is used instead of pure oxygen. This is because N2 acts as a diluent and reduces the concentration of oxygen, which prevents the formation of P4O10.
Reasons for using N2 and Oxygen mixture:
- Prevents the formation of P4O10: As mentioned earlier, the presence of excess oxygen leads to the formation of P4O10 instead of P4O6. The use of a mixture of N2 and oxygen helps to control the concentration of oxygen and prevent the formation of P4O10.
- Reduces the reactivity of phosphorus: Pure oxygen is highly reactive and can lead to the formation of undesired products. By diluting the oxygen with N2, the reactivity of phosphorus is reduced, which helps to control the reaction and prevent the formation of undesired products.
- Increases the safety of the reaction: The use of pure oxygen can lead to the formation of ozone, which is a powerful oxidizing agent and can be hazardous. By using a mixture of N2 and oxygen, the formation of ozone is prevented, which increases the safety of the reaction.
Conclusion:
In summary, the use of a mixture of N2 and oxygen in the preparation of P4O6 helps to prevent the formation of P4O10, reduces the reactivity of phosphorus, and increases the safety of the reaction.
Preparation of P4O6 requires the reaction of phosphorus with oxygen. However, in the presence of excess oxygen, P4O10 is formed instead of P4O6. To prevent this, a mixture of N2 and oxygen is used instead of pure oxygen. This is because N2 acts as a diluent and reduces the concentration of oxygen, which prevents the formation of P4O10.
Reasons for using N2 and Oxygen mixture:
- Prevents the formation of P4O10: As mentioned earlier, the presence of excess oxygen leads to the formation of P4O10 instead of P4O6. The use of a mixture of N2 and oxygen helps to control the concentration of oxygen and prevent the formation of P4O10.
- Reduces the reactivity of phosphorus: Pure oxygen is highly reactive and can lead to the formation of undesired products. By diluting the oxygen with N2, the reactivity of phosphorus is reduced, which helps to control the reaction and prevent the formation of undesired products.
- Increases the safety of the reaction: The use of pure oxygen can lead to the formation of ozone, which is a powerful oxidizing agent and can be hazardous. By using a mixture of N2 and oxygen, the formation of ozone is prevented, which increases the safety of the reaction.
Conclusion:
In summary, the use of a mixture of N2 and oxygen in the preparation of P4O6 helps to prevent the formation of P4O10, reduces the reactivity of phosphorus, and increases the safety of the reaction.
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In the preparation of P4O6, a mixture of N2 and oxygen is used instead...
If pure O2 gas used it will further oxidise P4O6 to P4O10. so here N2 helps in preventing further oxidation.
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In the preparation of P4O6, a mixture of N2 and oxygen is used instead of pure oxygen. The reason is:a)Pure oxygen will form ozone in presence of P.b)Pure oxygen will form P4O10 despite excess of P4, in pure oxygen.c)Pure oxygen will form [P(O3)4] ozonide.d)Pure oxygen will not react with P. N2 acts as a catalyst.Correct answer is option 'B'. Can you explain this answer? for Chemistry 2025 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about In the preparation of P4O6, a mixture of N2 and oxygen is used instead of pure oxygen. The reason is:a)Pure oxygen will form ozone in presence of P.b)Pure oxygen will form P4O10 despite excess of P4, in pure oxygen.c)Pure oxygen will form [P(O3)4] ozonide.d)Pure oxygen will not react with P. N2 acts as a catalyst.Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemistry 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the preparation of P4O6, a mixture of N2 and oxygen is used instead of pure oxygen. The reason is:a)Pure oxygen will form ozone in presence of P.b)Pure oxygen will form P4O10 despite excess of P4, in pure oxygen.c)Pure oxygen will form [P(O3)4] ozonide.d)Pure oxygen will not react with P. N2 acts as a catalyst.Correct answer is option 'B'. Can you explain this answer?.
In the preparation of P4O6, a mixture of N2 and oxygen is used instead of pure oxygen. The reason is:a)Pure oxygen will form ozone in presence of P.b)Pure oxygen will form P4O10 despite excess of P4, in pure oxygen.c)Pure oxygen will form [P(O3)4] ozonide.d)Pure oxygen will not react with P. N2 acts as a catalyst.Correct answer is option 'B'. Can you explain this answer? for Chemistry 2025 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about In the preparation of P4O6, a mixture of N2 and oxygen is used instead of pure oxygen. The reason is:a)Pure oxygen will form ozone in presence of P.b)Pure oxygen will form P4O10 despite excess of P4, in pure oxygen.c)Pure oxygen will form [P(O3)4] ozonide.d)Pure oxygen will not react with P. N2 acts as a catalyst.Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemistry 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the preparation of P4O6, a mixture of N2 and oxygen is used instead of pure oxygen. The reason is:a)Pure oxygen will form ozone in presence of P.b)Pure oxygen will form P4O10 despite excess of P4, in pure oxygen.c)Pure oxygen will form [P(O3)4] ozonide.d)Pure oxygen will not react with P. N2 acts as a catalyst.Correct answer is option 'B'. Can you explain this answer?.
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