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The curves x2 + y2=16 and y2 = 6x intersects at
- a)(0, 2√3)
- b)(0, 2)
- c)(2, 2√3)
- d)(2, 0)
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The curves x2+ y2=16 and y2= 6x intersects ata)(0, 2√3)b)...
x2 + y2=16 and y2 = 6x
So, to figure out the P.O.I
x2 + 6x = 16
x2 + 6x – 16 = 0
(x+8) (x-2) = 0
x = -8, 2
For x = -8
y = (6*(-8))1/2
= (-48)1/2
No real value for y
For x = 2
y = (6*2)1/2
= (12)1/2
= 2*(3)1/2
So, P.O.I is (2 , 2*(3)1/2 )
So, to figure out the P.O.I
x2 + 6x = 16
x2 + 6x – 16 = 0
(x+8) (x-2) = 0
x = -8, 2
For x = -8
y = (6*(-8))1/2
= (-48)1/2
No real value for y
For x = 2
y = (6*2)1/2
= (12)1/2
= 2*(3)1/2
So, P.O.I is (2 , 2*(3)1/2 )
Most Upvoted Answer
The curves x2+ y2=16 and y2= 6x intersects ata)(0, 2√3)b)...
x2 + y2=16 and y2 = 6x
So, to figure out the P.O.I
x2 + 6x = 16
x2 + 6x – 16 = 0
(x+8) (x-2) = 0
x = -8, 2
For x = -8
y = (6*(-8))1/2
= (-48)1/2
No real value for y
For x = 2
y = (6*2)1/2
= (12)1/2
= 2*(3)1/2
So, P.O.I is (2 , 2*(3)1/2 )
So, to figure out the P.O.I
x2 + 6x = 16
x2 + 6x – 16 = 0
(x+8) (x-2) = 0
x = -8, 2
For x = -8
y = (6*(-8))1/2
= (-48)1/2
No real value for y
For x = 2
y = (6*2)1/2
= (12)1/2
= 2*(3)1/2
So, P.O.I is (2 , 2*(3)1/2 )
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The curves x2+ y2=16 and y2= 6x intersects ata)(0, 2√3)b)(0, 2)c)(2, 2√3)d)(2, 0)Correct answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The curves x2+ y2=16 and y2= 6x intersects ata)(0, 2√3)b)(0, 2)c)(2, 2√3)d)(2, 0)Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The curves x2+ y2=16 and y2= 6x intersects ata)(0, 2√3)b)(0, 2)c)(2, 2√3)d)(2, 0)Correct answer is option 'C'. Can you explain this answer?.
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