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The inversion of cane sugar proceeds with half-life of 500 minutes at pH 5 for any concentration of sugar. However if pH = 6, the half-life changes to 50 minute. The rate law expression for the sugar inversion can be written as:
- a)r = K[sugar]2[H]6
- b)r = K[sugar]1[H]0
- c)r = K[sugar]0[H+]6
- d)r = K[sugar]0[H+]1
Correct answer is option 'B'. Can you explain this answer?
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Explanation:
The rate law expression gives the relationship between the rate of a reaction and the concentrations of the reactants. In this case, we are given that the rate law expression for the sugar inversion is of the form r = K[sugar]a[H]b, where r is the rate of the reaction, [sugar] is the concentration of sugar, [H] is the concentration of hydrogen ions, and a and b are the respective orders of the reaction with respect to sugar and hydrogen ions.
Effect of pH on the half-life:
We are given that the half-life of the inversion reaction changes from 500 minutes at pH 5 to 50 minutes at pH 6. The half-life of a reaction is the time it takes for the concentration of the reactant to decrease by half. A shorter half-life indicates a faster reaction, while a longer half-life indicates a slower reaction.
Effect of pH on the rate constant:
The rate constant (K) is a proportionality constant that relates the rate of a reaction to the concentrations of the reactants. In this case, we can observe that the rate of the inversion reaction increases by a factor of 10 (from 500 minutes to 50 minutes) when the pH increases from 5 to 6. This suggests that the rate constant (K) is 10 times larger at pH 6 compared to pH 5.
Determination of the rate law expression:
Since the rate constant (K) is dependent on pH, it implies that the rate of the reaction is directly influenced by the concentration of hydrogen ions ([H]). We can conclude that the order of the reaction with respect to hydrogen ions is 0 (as the concentration of hydrogen ions does not affect the rate of the reaction).
Therefore, the rate law expression for the sugar inversion can be simplified to r = K[sugar]a, where a is the order of the reaction with respect to sugar. The only option that matches this simplified rate law expression is option B: r = K[sugar]1[H]0.
Thus, option B is the correct answer.
The rate law expression gives the relationship between the rate of a reaction and the concentrations of the reactants. In this case, we are given that the rate law expression for the sugar inversion is of the form r = K[sugar]a[H]b, where r is the rate of the reaction, [sugar] is the concentration of sugar, [H] is the concentration of hydrogen ions, and a and b are the respective orders of the reaction with respect to sugar and hydrogen ions.
Effect of pH on the half-life:
We are given that the half-life of the inversion reaction changes from 500 minutes at pH 5 to 50 minutes at pH 6. The half-life of a reaction is the time it takes for the concentration of the reactant to decrease by half. A shorter half-life indicates a faster reaction, while a longer half-life indicates a slower reaction.
Effect of pH on the rate constant:
The rate constant (K) is a proportionality constant that relates the rate of a reaction to the concentrations of the reactants. In this case, we can observe that the rate of the inversion reaction increases by a factor of 10 (from 500 minutes to 50 minutes) when the pH increases from 5 to 6. This suggests that the rate constant (K) is 10 times larger at pH 6 compared to pH 5.
Determination of the rate law expression:
Since the rate constant (K) is dependent on pH, it implies that the rate of the reaction is directly influenced by the concentration of hydrogen ions ([H]). We can conclude that the order of the reaction with respect to hydrogen ions is 0 (as the concentration of hydrogen ions does not affect the rate of the reaction).
Therefore, the rate law expression for the sugar inversion can be simplified to r = K[sugar]a, where a is the order of the reaction with respect to sugar. The only option that matches this simplified rate law expression is option B: r = K[sugar]1[H]0.
Thus, option B is the correct answer.
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The inversion of cane sugar proceeds with half-life of 500 minutes at pH 5 for any concentration of sugar. However if pH = 6, the half-life changes to 50 minute. The rate law expression for the sugar inversion can be written as:a)r = K[sugar]2[H]6b)r = K[sugar]1[H]0c)r = K[sugar]0[H+]6d)r = K[sugar]0[H+]1Correct answer is option 'B'. Can you explain this answer?
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The inversion of cane sugar proceeds with half-life of 500 minutes at pH 5 for any concentration of sugar. However if pH = 6, the half-life changes to 50 minute. The rate law expression for the sugar inversion can be written as:a)r = K[sugar]2[H]6b)r = K[sugar]1[H]0c)r = K[sugar]0[H+]6d)r = K[sugar]0[H+]1Correct answer is option 'B'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The inversion of cane sugar proceeds with half-life of 500 minutes at pH 5 for any concentration of sugar. However if pH = 6, the half-life changes to 50 minute. The rate law expression for the sugar inversion can be written as:a)r = K[sugar]2[H]6b)r = K[sugar]1[H]0c)r = K[sugar]0[H+]6d)r = K[sugar]0[H+]1Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The inversion of cane sugar proceeds with half-life of 500 minutes at pH 5 for any concentration of sugar. However if pH = 6, the half-life changes to 50 minute. The rate law expression for the sugar inversion can be written as:a)r = K[sugar]2[H]6b)r = K[sugar]1[H]0c)r = K[sugar]0[H+]6d)r = K[sugar]0[H+]1Correct answer is option 'B'. Can you explain this answer?.
The inversion of cane sugar proceeds with half-life of 500 minutes at pH 5 for any concentration of sugar. However if pH = 6, the half-life changes to 50 minute. The rate law expression for the sugar inversion can be written as:a)r = K[sugar]2[H]6b)r = K[sugar]1[H]0c)r = K[sugar]0[H+]6d)r = K[sugar]0[H+]1Correct answer is option 'B'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The inversion of cane sugar proceeds with half-life of 500 minutes at pH 5 for any concentration of sugar. However if pH = 6, the half-life changes to 50 minute. The rate law expression for the sugar inversion can be written as:a)r = K[sugar]2[H]6b)r = K[sugar]1[H]0c)r = K[sugar]0[H+]6d)r = K[sugar]0[H+]1Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The inversion of cane sugar proceeds with half-life of 500 minutes at pH 5 for any concentration of sugar. However if pH = 6, the half-life changes to 50 minute. The rate law expression for the sugar inversion can be written as:a)r = K[sugar]2[H]6b)r = K[sugar]1[H]0c)r = K[sugar]0[H+]6d)r = K[sugar]0[H+]1Correct answer is option 'B'. Can you explain this answer?.
Solutions for The inversion of cane sugar proceeds with half-life of 500 minutes at pH 5 for any concentration of sugar. However if pH = 6, the half-life changes to 50 minute. The rate law expression for the sugar inversion can be written as:a)r = K[sugar]2[H]6b)r = K[sugar]1[H]0c)r = K[sugar]0[H+]6d)r = K[sugar]0[H+]1Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry.
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Here you can find the meaning of The inversion of cane sugar proceeds with half-life of 500 minutes at pH 5 for any concentration of sugar. However if pH = 6, the half-life changes to 50 minute. The rate law expression for the sugar inversion can be written as:a)r = K[sugar]2[H]6b)r = K[sugar]1[H]0c)r = K[sugar]0[H+]6d)r = K[sugar]0[H+]1Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The inversion of cane sugar proceeds with half-life of 500 minutes at pH 5 for any concentration of sugar. However if pH = 6, the half-life changes to 50 minute. The rate law expression for the sugar inversion can be written as:a)r = K[sugar]2[H]6b)r = K[sugar]1[H]0c)r = K[sugar]0[H+]6d)r = K[sugar]0[H+]1Correct answer is option 'B'. Can you explain this answer?, a detailed solution for The inversion of cane sugar proceeds with half-life of 500 minutes at pH 5 for any concentration of sugar. However if pH = 6, the half-life changes to 50 minute. The rate law expression for the sugar inversion can be written as:a)r = K[sugar]2[H]6b)r = K[sugar]1[H]0c)r = K[sugar]0[H+]6d)r = K[sugar]0[H+]1Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of The inversion of cane sugar proceeds with half-life of 500 minutes at pH 5 for any concentration of sugar. However if pH = 6, the half-life changes to 50 minute. The rate law expression for the sugar inversion can be written as:a)r = K[sugar]2[H]6b)r = K[sugar]1[H]0c)r = K[sugar]0[H+]6d)r = K[sugar]0[H+]1Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The inversion of cane sugar proceeds with half-life of 500 minutes at pH 5 for any concentration of sugar. However if pH = 6, the half-life changes to 50 minute. The rate law expression for the sugar inversion can be written as:a)r = K[sugar]2[H]6b)r = K[sugar]1[H]0c)r = K[sugar]0[H+]6d)r = K[sugar]0[H+]1Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice Chemistry tests.
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