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An air filled rectangular wave guide has dimensions a = 2, b = 1 cm, the range of frequencies over which guide will operate in single mode is given by:
  • a)
    7.5 GHz < f < 10 GHz
  • b)
    f < 16 GHz
  • c)
    7.5 GHz < f < 22.5 GHz
  • d)
    7.5 GHz < f < 15 GHz
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
An air filled rectangular wave guide has dimensions a = 2, b = 1 cm, t...
single mode propagation means only TE|0 mode will propagate.
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An air filled rectangular wave guide has dimensions a = 2, b = 1 cm, t...
Given:
a = 2 cm
b = 1 cm

To find:
The range of frequencies over which the guide will operate in a single mode.

Solution:
The cutoff frequency for the dominant mode in a rectangular waveguide is given by:

fc = (c/2π) √( (m/a)^2 + (n/b)^2 )

Where,
c = speed of light = 3 × 10^8 m/s
m, n = mode numbers

For single-mode operation, m = 1 and n = 0 or vice versa.

So, the cutoff frequency for the TE10 mode is given by:

fc = (c/2π) (1/a)

Substituting the given values, we get:

fc = (3 × 10^8/2π)(1/0.02) = 7.5 GHz

The operating frequency range for single-mode operation is usually taken as 1.5 times the cutoff frequency. So,

fmin = 1.5 × fc = 11.25 GHz

fmax = 1.5 × fc = 11.25 GHz

Therefore, the range of frequencies over which the guide will operate in single mode is:

7.5 GHz ≤ f ≤ 11.25 GHz
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