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The density of a gas at 27°C and 1 atm is d. Pressure remaining constant at which temperature(K) will its density become 0.75 d: [rounded up to two decimal places]
    Correct answer is between '398.00,402.00'. Can you explain this answer?
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    The density of a gas at 27°C and 1 atm is d. Pressure remaining co...
    As we know that, PV = nRT

    or PV = (m/M) RT

    or PM = (m/V) RT = d RT

    In condition (1):  PV = d R 300

    In condition (2): PV = 0.75d​ RT

    Dividing condition (1) by (2), we get:

    1 = (300)/0.75T

    or T = 400 K
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    The density of a gas at 27°C and 1 atm is d. Pressure remaining co...
    The density of a gas at 27°C can vary depending on the specific gas and its conditions. However, in general, the density of a gas can be calculated using the ideal gas law. The ideal gas law states that:

    PV = nRT

    Where:
    P = pressure of the gas
    V = volume of the gas
    n = number of moles of gas
    R = ideal gas constant
    T = temperature in Kelvin

    To calculate the density of a gas, we need to rearrange the ideal gas law to solve for density:

    density = (n * M) / V

    Where:
    density = density of the gas
    M = molar mass of the gas

    Keep in mind that the temperature needs to be converted from Celsius to Kelvin by adding 273.15.

    So, to calculate the density of a gas at 27°C, you would need to know the specific gas and its molar mass, as well as the pressure and volume of the gas.
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    The density of a gas at 27°C and 1 atm is d. Pressure remaining constant at which temperature(K) will its density become 0.75 d: [rounded up to two decimal places]Correct answer is between '398.00,402.00'. Can you explain this answer?
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