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The equation of the parabola with vertex at (0, 0) and focus at (0, – 2) is:
  • a)
    y2 = – 2x
  • b)
    x2 = – 8y
  • c)
    y2 = – 8x
  • d)
    x2 = – 4y
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The equation of the parabola with vertex at (0, 0) and focus at (0, &n...
Given the vertex of the parabola is (0,0) and focus is at (0,-2).
This gives the axis of the parabola is the positive y− axis.
Then the equation of the parabola will be x^2 = 4ay where a = -2.
So the equation of the parabola is x2 = -8y.
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The equation of the parabola with vertex at (0, 0) and focus at (0, &n...
Understanding the Parabola
A parabola is defined by its focus and directrix. The vertex is the midpoint between these two points. In this case, we have:
- Vertex: (0, 0)
- Focus: (0, -2)
Orientation of the Parabola
Since the focus is located below the vertex, the parabola opens downward. The standard form of a parabola that opens vertically is given by:
- Equation: y² = 4px
Where 'p' is the distance from the vertex to the focus.
Calculating p
The distance from the vertex (0, 0) to the focus (0, -2) is 2 units. Hence, p = -2 (negative because it opens downward).
Forming the Equation
Substituting p into the standard form:
- y² = 4(-2)x
- y² = -8x
Thus, the equation of the parabola becomes:
Final Equation
- y² = -8x
This matches option (b).
Conclusion
The correct equation for the parabola with a vertex at (0, 0) and a focus at (0, -2) is indeed:
- y² = -8x
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The equation of the parabola with vertex at (0, 0) and focus at (0, – 2) is:a)y2= – 2xb)x2= – 8yc)y2= – 8xd)x2= – 4yCorrect answer is option 'B'. Can you explain this answer?
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