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An urn contains 3 red and 2 black balls. Two balls are randomly drawn. Let X represents the number of black balls. The possible values of X are:​
  • a)
    1 & 2
  • b)
    0, 1 & 2
  • c)
    0, 1, 2 & 3
  • d)
    1, 2 & 3
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
An urn contains 3 red and 2 black balls. Two balls are randomly drawn....
Given that an urn has 3 Red balls and 2 Black balls.
The number of ways in which two balls can be reprsented are {(RR), (RB), (BR), (BB)}
Let X represent the number of black balls. Possible values of X are: X (RR) = 0, X (RB) = 1, X(BR = 1) and X (BB) = 2.
Therefore the possible values of X are 0, 1 and 2.
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Most Upvoted Answer
An urn contains 3 red and 2 black balls. Two balls are randomly drawn....
The number of ways in which two balls can be represented are {(RR), (RB), (BR), (BB)}
Let X represent the number of black balls. Possible values of X are:
 X (RR) = 0, X (RB) = 1, 
 X(BR) 1 and X (BB) = 2.
Therefore the possible values of X are 0, 1 and 2.
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An urn contains 3 red and 2 black balls. Two balls are randomly drawn. Let X represents the number of black balls. The possible values of X are:​a)1 & 2b)0, 1 & 2c)0, 1, 2 & 3d)1, 2 & 3Correct answer is option 'B'. Can you explain this answer?
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