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0.5 mole of each of H2, SO2 and CH4 are kept in a container. A hole was made in the container. After 3 hours, the order of partial pressures in the container will be:           
  • a)
    pSO2 > pCH4 > pH2                                                 
  • b)
    pH2 > pSO2 > pCH          
  • c)
    pH2 > pCH4 > pSO2                                                 
  • d)
    pSO2 > pH2 > pCH4
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
0.5 mole of each of H2, SO2 and CH4 are kept in a container. A hole wa...
The order of partial pressures cannot be determined without additional information about the reaction or the conditions of the container.
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0.5 mole of each of H2, SO2 and CH4 are kept in a container. A hole wa...
Rate of diffusion is inversely proportional to square root of molecular weight.
Molecular weight: SO2> CH4> H2
Rate of diffusion: H2> CH4> SO2.

Amount of Gases remained in container after 3 hrs: SO2>CH4> H2.
Since SO2 is present in maximum amount in container... so maximum pressure in container will be of SO2.
Order of pressure exerted in container after 3 hrs: SO2> CH4> H2.
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0.5 mole of each of H2, SO2 and CH4 are kept in a container. A hole was made in the container. After 3 hours, the order of partial pressures in the container will be:a)pSO2 > pCH4 > pH2b)pH2 > pSO2 > pCH4c)pH2 > pCH4 > pSO2d)pSO2 > pH2 > pCH4Correct answer is option 'A'. Can you explain this answer?
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