Select 18e– species among following:a)CpMo(CO)3b)(η5-Cp)Fe(C...
Explanation:
Given Species:
a) CpMo(CO)3
b) (η5-Cp)Fe(CO)2Cl
c) CH3Mn(CO)5
Selection of 18e⁻ species:
- An 18-electron species in organometallic chemistry is a species that has 18 valence electrons around the metal center.
- This electron count is often associated with stable coordination complexes.
Analysis:
- CpMo(CO)3: This species contains 3 carbonyl ligands and one cyclopentadienyl ligand, contributing a total of 3 + 5 = 8 electrons. Therefore, the Mo center in this compound has a 12-electron count.
- (η5-Cp)Fe(CO)2Cl: This species contains one cyclopentadienyl ligand (5 electrons), two carbonyl ligands (2 x 2 = 4 electrons), and a chloride ligand (1 electron), totaling 10 electrons. Hence, the Fe center in this compound has an 8-electron count.
- CH3Mn(CO)5: This compound consists of 5 carbonyl ligands (5 x 2 = 10 electrons) and a methyl ligand (1 electron), resulting in a 11-electron count for the Mn center.
Selection:
- Among the given species, both 'b' and 'c' can be considered as 18-electron species.
- The (η5-Cp)Fe(CO)2Cl complex has an 8-electron count at the Fe center, while CH3Mn(CO)5 has an 11-electron count at the Mn center.
- Thus, both 'b' and 'c' fulfill the criteria of being 18-electron species in organometallic chemistry.
Therefore, the correct answer is option 'D' - Both 'b' and 'c'.