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The 4 byte IP address consists of
  • a)
    network address
  • b)
    host address
  • c)
    both (a) and (b)
  • d)
    none of the mentioned
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
The 4 byte IP address consists ofa)network addressb)host addressc)both...
Explanation:

  • The 4 byte IP address consists of both network address and host address.

  • The IP address is divided into two parts, the network address and the host address.

  • The network address is used to identify the network, while the host address is used to identify the specific device on that network.

  • The network address is determined by the class of IP address, which can be Class A, B, or C.

  • The host address is determined by the subnet mask, which is used to divide the network into smaller subnetworks.

  • Together, the network address and the host address make up the complete IP address, which is used to route data between devices on different networks.

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The 4 byte IP address consists ofa)network addressb)host addressc)both...
An IPv4 address consists of 32 bits, the most significant part indicates the network prefix and the remaining bits indicate the host. The number of bits which indicate the network and the host depend upon the IP class (in classful addressing) or the variable length subnet mask (in CIDR).
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A processor uses 2-level page tables for virtual to physical address translation. Page tables for both levels are stored in the main memory. Virtual and physical addresses are both 32 bits wide. The memory is byte addressable. For virtual to physical address translation, the 10 most significant bits of the virtual address are used as index into the first level page table while the next 10 bits are used as index into the second level page table. The 12 least significant bits of the virtual address are used as offset within the page. Assume that the page table entries in both levels of page tables are 4 bytes wide. Further, the processor has a translation look-aside buffer (TLB), with a hit rate of 96%. The TLB caches recently used virtual page numbers and the corresponding physical page numbers. The processor also has a physically addressed cache with a hit rate of 90%. Main memory access time is 10 ns, cache access time is 1 ns, and TLB access time is also 1 ns. Suppose a process has only the following pages in its virtual address space: two contiguous code pages starting at virtual address 0x00000000, two contiguous data pages starting at virtual address 000400000, and a stack page starting at virtual address 0FFFFF000. The amount of memory required for storing the page tables of this process is

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The 4 byte IP address consists ofa)network addressb)host addressc)both (a) and (b)d)none of the mentionedCorrect answer is option 'C'. Can you explain this answer?
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