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Molybdoenzymes can both oxidize as well as reduce the substrates, because:
  • a)
    Mo(VI) is more stable than Mo(IV).
  • b)
    Mo(IV) can transfer oxygen atom to the substrate and Mo(VI) can abstract oxygen atom from the substrate.
  • c)
    Conversion of Mo(VI) to Mo(IV) is not favoured.
  • d)
    Mo(VI) can transfer oxygen atom to the substrate and Mo(IV) can abstract oxygen atom from the substrate.
Correct answer is option 'D'. Can you explain this answer?
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Molybdoenzymes can both oxidize as well as reduce the substrates, beca...
-Molybdoenzymes are an ancient protein family found in phylogenetically and ecologically diverse prokaryotes. Under anaerobic conditions, respiratory molybdoenzymes catalyze redox reactions that transfer electrons to a variety of substrates that act as terminal electron acceptors for energy generation.
-Molybdoenzymes can both oxidize as well as reduce the substrates, because Mo(VI) can transfer oxygen atom to the substrate and Mo(IV) can abstract oxygen atom from the substrate.

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Molybdoenzymes can both oxidize as well as reduce the substrates, beca...
Molybdoenzymes are enzymes that contain molybdenum as a cofactor. These enzymes can both oxidize and reduce substrates because of the following reasons:

Transfer of Oxygen Atom
Mo(VI) in molybdoenzymes can transfer an oxygen atom to the substrate, while Mo(IV) can abstract an oxygen atom from the substrate. This ability of molybdoenzymes to transfer and abstract oxygen atoms allows them to act as both oxidases and reductases.

Stability of Mo(VI) and Mo(IV)
Mo(VI) is more stable than Mo(IV), which makes it easier for molybdoenzymes to transfer an oxygen atom to the substrate. On the other hand, conversion of Mo(VI) to Mo(IV) is not favored, which makes it easier for molybdoenzymes to abstract an oxygen atom from the substrate.

Overall, the ability of molybdoenzymes to both oxidize and reduce substrates is due to the transfer and abstraction of oxygen atoms by Mo(VI) and Mo(IV), respectively. This ability allows molybdoenzymes to play a vital role in various metabolic processes in organisms.
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Molybdoenzymes can both oxidize as well as reduce the substrates, because:a)Mo(VI) is more stable than Mo(IV).b)Mo(IV) can transfer oxygen atom to the substrate and Mo(VI) can abstract oxygen atom from the substrate.c)Conversion of Mo(VI) to Mo(IV) is not favoured.d)Mo(VI) can transfer oxygen atom to the substrate and Mo(IV) can abstract oxygen atom from the substrate.Correct answer is option 'D'. Can you explain this answer?
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Molybdoenzymes can both oxidize as well as reduce the substrates, because:a)Mo(VI) is more stable than Mo(IV).b)Mo(IV) can transfer oxygen atom to the substrate and Mo(VI) can abstract oxygen atom from the substrate.c)Conversion of Mo(VI) to Mo(IV) is not favoured.d)Mo(VI) can transfer oxygen atom to the substrate and Mo(IV) can abstract oxygen atom from the substrate.Correct answer is option 'D'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Molybdoenzymes can both oxidize as well as reduce the substrates, because:a)Mo(VI) is more stable than Mo(IV).b)Mo(IV) can transfer oxygen atom to the substrate and Mo(VI) can abstract oxygen atom from the substrate.c)Conversion of Mo(VI) to Mo(IV) is not favoured.d)Mo(VI) can transfer oxygen atom to the substrate and Mo(IV) can abstract oxygen atom from the substrate.Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Molybdoenzymes can both oxidize as well as reduce the substrates, because:a)Mo(VI) is more stable than Mo(IV).b)Mo(IV) can transfer oxygen atom to the substrate and Mo(VI) can abstract oxygen atom from the substrate.c)Conversion of Mo(VI) to Mo(IV) is not favoured.d)Mo(VI) can transfer oxygen atom to the substrate and Mo(IV) can abstract oxygen atom from the substrate.Correct answer is option 'D'. Can you explain this answer?.
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