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If If ω is a non real cube root of unity and (1+ω)= a+bω;a,b ∈ R, then a and b are respectively the numbers :
  • a)
    1, 0
  • b)
    -1, 0
  • c)
    0, 1
  • d)
    0, -1
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
If Ifωis a non real cube root of unity and(1+ω)9= a+b&omeg...
Since w is the cube root of unity.
(1+w)9 =A+Bw
⇒(−w2)9 =A+Bw
⇒−(w3)6 = A+Bw
⇒−1=A+Bw
∴ A= -1 & B=0
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Most Upvoted Answer
If Ifωis a non real cube root of unity and(1+ω)9= a+b&omeg...
Since w is the cube root of unity.
(1+w)9 =A+Bw
⇒(−w2)9 =A+Bw
⇒−(w3)6 = A+Bw
⇒−1=A+Bw
∴ A= -1 & B=0
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Community Answer
If Ifωis a non real cube root of unity and(1+ω)9= a+b&omeg...
Since w is the cube root of unity.
(1+w)9 =A+Bw
⇒(−w2)9 =A+Bw
⇒−(w3)6 = A+Bw
⇒−1=A+Bw
∴ A= -1 & B=0
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If Ifωis a non real cube root of unity and(1+ω)9= a+bω;a,b ∈ R, then a and b are respectively the numbers :a)1, 0b)-1, 0c)0, 1d)0, -1Correct answer is option 'B'. Can you explain this answer?
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If Ifωis a non real cube root of unity and(1+ω)9= a+bω;a,b ∈ R, then a and b are respectively the numbers :a)1, 0b)-1, 0c)0, 1d)0, -1Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If Ifωis a non real cube root of unity and(1+ω)9= a+bω;a,b ∈ R, then a and b are respectively the numbers :a)1, 0b)-1, 0c)0, 1d)0, -1Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If Ifωis a non real cube root of unity and(1+ω)9= a+bω;a,b ∈ R, then a and b are respectively the numbers :a)1, 0b)-1, 0c)0, 1d)0, -1Correct answer is option 'B'. Can you explain this answer?.
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