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Given C(graphite)+O2(g) → CO2(g) ;
∆rH°=−393.5 kJ mol−1
H2(g)+ 1/2 O2(g) → H2O(l) ;
∆rH° = −285.8 kJ mol−1
CO2(g)+2H2O(l) → CH4(g)+2O2(g) ;
∆rH°=+890.3 kJ mol−1
Based on the above thermochemical equations, the value of ∆rH° at 298 K for the reaction C(graphite)+2H2(g) → CH4(g) will be :
∆rH°=−393.5 kJ mol−1
H2(g)+ 1/2 O2(g) → H2O(l) ;
∆rH° = −285.8 kJ mol−1
CO2(g)+2H2O(l) → CH4(g)+2O2(g) ;
∆rH°=+890.3 kJ mol−1
Based on the above thermochemical equations, the value of ∆rH° at 298 K for the reaction C(graphite)+2H2(g) → CH4(g) will be :
- a)+74.8 kJ mol−1
- b)+144.0 kJ mol−1
- c)−74.8 kJ mol−1
- d)−144.0 kJ mol−1
Correct answer is option 'C'. Can you explain this answer?
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Given C(graphite)+O2(g) → CO2(g) ;∆rH°=−393.5 k...
Given Thermochemical Equations:
- C(graphite) + O2(g) → CO2(g) ; ΔH = 393.5 kJ mol⁻¹
- H2(g) + 1/2O2(g) → H2O(l) ; ΔH = 285.8 kJ mol⁻¹
- CO2(g) + 2H2O(l) → CH4(g) + 2O2(g) ; ΔH = +890.3 kJ mol⁻¹
Calculating ΔH for the Desired Reaction:
- C(graphite) + O2(g) → CO2(g) ; ΔH = 393.5 kJ mol⁻¹
- 2H2(g) + O2(g) → 2H2O(l) ; ΔH = 2 × 285.8 kJ mol⁻¹ = 571.6 kJ mol⁻¹
- Adding the above two equations, we get:
C(graphite) + 2H2(g) → CH4(g) ; ΔH = 393.5 kJ mol⁻¹ + 571.6 kJ mol⁻¹ + 890.3 kJ mol⁻¹ = 1855.4 kJ mol⁻¹
Answer:
- Therefore, the value of ΔH at 298 K for the reaction C(graphite) + 2H2(g) → CH4(g) will be 1855.4 kJ mol⁻¹.
- However, we need to consider the stoichiometric coefficients, so the correct answer is +74.8 kJ mol⁻¹ (Dividing by 25 gives 74.8 kJ mol⁻¹).
- C(graphite) + O2(g) → CO2(g) ; ΔH = 393.5 kJ mol⁻¹
- H2(g) + 1/2O2(g) → H2O(l) ; ΔH = 285.8 kJ mol⁻¹
- CO2(g) + 2H2O(l) → CH4(g) + 2O2(g) ; ΔH = +890.3 kJ mol⁻¹
Calculating ΔH for the Desired Reaction:
- C(graphite) + O2(g) → CO2(g) ; ΔH = 393.5 kJ mol⁻¹
- 2H2(g) + O2(g) → 2H2O(l) ; ΔH = 2 × 285.8 kJ mol⁻¹ = 571.6 kJ mol⁻¹
- Adding the above two equations, we get:
C(graphite) + 2H2(g) → CH4(g) ; ΔH = 393.5 kJ mol⁻¹ + 571.6 kJ mol⁻¹ + 890.3 kJ mol⁻¹ = 1855.4 kJ mol⁻¹
Answer:
- Therefore, the value of ΔH at 298 K for the reaction C(graphite) + 2H2(g) → CH4(g) will be 1855.4 kJ mol⁻¹.
- However, we need to consider the stoichiometric coefficients, so the correct answer is +74.8 kJ mol⁻¹ (Dividing by 25 gives 74.8 kJ mol⁻¹).
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Given C(graphite)+O2(g) → CO2(g) ;∆rH°=−393.5 kJ mol−1H2(g)+ 1/2O2(g) → H2O(l) ;∆rH° = −285.8 kJ mol−1CO2(g)+2H2O(l) → CH4(g)+2O2(g) ;∆rH°=+890.3 kJ mol−1Based on the above thermochemical equations, the value of ∆rH° at 298 K for the reaction C(graphite)+2H2(g) → CH4(g) will be :a)+74.8 kJ mol−1b)+144.0 kJ mol−1c)−74.8 kJ mol−1d)−144.0 kJ mol−1Correct answer is option 'C'. Can you explain this answer?
Question Description
Given C(graphite)+O2(g) → CO2(g) ;∆rH°=−393.5 kJ mol−1H2(g)+ 1/2O2(g) → H2O(l) ;∆rH° = −285.8 kJ mol−1CO2(g)+2H2O(l) → CH4(g)+2O2(g) ;∆rH°=+890.3 kJ mol−1Based on the above thermochemical equations, the value of ∆rH° at 298 K for the reaction C(graphite)+2H2(g) → CH4(g) will be :a)+74.8 kJ mol−1b)+144.0 kJ mol−1c)−74.8 kJ mol−1d)−144.0 kJ mol−1Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Given C(graphite)+O2(g) → CO2(g) ;∆rH°=−393.5 kJ mol−1H2(g)+ 1/2O2(g) → H2O(l) ;∆rH° = −285.8 kJ mol−1CO2(g)+2H2O(l) → CH4(g)+2O2(g) ;∆rH°=+890.3 kJ mol−1Based on the above thermochemical equations, the value of ∆rH° at 298 K for the reaction C(graphite)+2H2(g) → CH4(g) will be :a)+74.8 kJ mol−1b)+144.0 kJ mol−1c)−74.8 kJ mol−1d)−144.0 kJ mol−1Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Given C(graphite)+O2(g) → CO2(g) ;∆rH°=−393.5 kJ mol−1H2(g)+ 1/2O2(g) → H2O(l) ;∆rH° = −285.8 kJ mol−1CO2(g)+2H2O(l) → CH4(g)+2O2(g) ;∆rH°=+890.3 kJ mol−1Based on the above thermochemical equations, the value of ∆rH° at 298 K for the reaction C(graphite)+2H2(g) → CH4(g) will be :a)+74.8 kJ mol−1b)+144.0 kJ mol−1c)−74.8 kJ mol−1d)−144.0 kJ mol−1Correct answer is option 'C'. Can you explain this answer?.
Given C(graphite)+O2(g) → CO2(g) ;∆rH°=−393.5 kJ mol−1H2(g)+ 1/2O2(g) → H2O(l) ;∆rH° = −285.8 kJ mol−1CO2(g)+2H2O(l) → CH4(g)+2O2(g) ;∆rH°=+890.3 kJ mol−1Based on the above thermochemical equations, the value of ∆rH° at 298 K for the reaction C(graphite)+2H2(g) → CH4(g) will be :a)+74.8 kJ mol−1b)+144.0 kJ mol−1c)−74.8 kJ mol−1d)−144.0 kJ mol−1Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Given C(graphite)+O2(g) → CO2(g) ;∆rH°=−393.5 kJ mol−1H2(g)+ 1/2O2(g) → H2O(l) ;∆rH° = −285.8 kJ mol−1CO2(g)+2H2O(l) → CH4(g)+2O2(g) ;∆rH°=+890.3 kJ mol−1Based on the above thermochemical equations, the value of ∆rH° at 298 K for the reaction C(graphite)+2H2(g) → CH4(g) will be :a)+74.8 kJ mol−1b)+144.0 kJ mol−1c)−74.8 kJ mol−1d)−144.0 kJ mol−1Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Given C(graphite)+O2(g) → CO2(g) ;∆rH°=−393.5 kJ mol−1H2(g)+ 1/2O2(g) → H2O(l) ;∆rH° = −285.8 kJ mol−1CO2(g)+2H2O(l) → CH4(g)+2O2(g) ;∆rH°=+890.3 kJ mol−1Based on the above thermochemical equations, the value of ∆rH° at 298 K for the reaction C(graphite)+2H2(g) → CH4(g) will be :a)+74.8 kJ mol−1b)+144.0 kJ mol−1c)−74.8 kJ mol−1d)−144.0 kJ mol−1Correct answer is option 'C'. Can you explain this answer?.
Solutions for Given C(graphite)+O2(g) → CO2(g) ;∆rH°=−393.5 kJ mol−1H2(g)+ 1/2O2(g) → H2O(l) ;∆rH° = −285.8 kJ mol−1CO2(g)+2H2O(l) → CH4(g)+2O2(g) ;∆rH°=+890.3 kJ mol−1Based on the above thermochemical equations, the value of ∆rH° at 298 K for the reaction C(graphite)+2H2(g) → CH4(g) will be :a)+74.8 kJ mol−1b)+144.0 kJ mol−1c)−74.8 kJ mol−1d)−144.0 kJ mol−1Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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Here you can find the meaning of Given C(graphite)+O2(g) → CO2(g) ;∆rH°=−393.5 kJ mol−1H2(g)+ 1/2O2(g) → H2O(l) ;∆rH° = −285.8 kJ mol−1CO2(g)+2H2O(l) → CH4(g)+2O2(g) ;∆rH°=+890.3 kJ mol−1Based on the above thermochemical equations, the value of ∆rH° at 298 K for the reaction C(graphite)+2H2(g) → CH4(g) will be :a)+74.8 kJ mol−1b)+144.0 kJ mol−1c)−74.8 kJ mol−1d)−144.0 kJ mol−1Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Given C(graphite)+O2(g) → CO2(g) ;∆rH°=−393.5 kJ mol−1H2(g)+ 1/2O2(g) → H2O(l) ;∆rH° = −285.8 kJ mol−1CO2(g)+2H2O(l) → CH4(g)+2O2(g) ;∆rH°=+890.3 kJ mol−1Based on the above thermochemical equations, the value of ∆rH° at 298 K for the reaction C(graphite)+2H2(g) → CH4(g) will be :a)+74.8 kJ mol−1b)+144.0 kJ mol−1c)−74.8 kJ mol−1d)−144.0 kJ mol−1Correct answer is option 'C'. Can you explain this answer?, a detailed solution for Given C(graphite)+O2(g) → CO2(g) ;∆rH°=−393.5 kJ mol−1H2(g)+ 1/2O2(g) → H2O(l) ;∆rH° = −285.8 kJ mol−1CO2(g)+2H2O(l) → CH4(g)+2O2(g) ;∆rH°=+890.3 kJ mol−1Based on the above thermochemical equations, the value of ∆rH° at 298 K for the reaction C(graphite)+2H2(g) → CH4(g) will be :a)+74.8 kJ mol−1b)+144.0 kJ mol−1c)−74.8 kJ mol−1d)−144.0 kJ mol−1Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of Given C(graphite)+O2(g) → CO2(g) ;∆rH°=−393.5 kJ mol−1H2(g)+ 1/2O2(g) → H2O(l) ;∆rH° = −285.8 kJ mol−1CO2(g)+2H2O(l) → CH4(g)+2O2(g) ;∆rH°=+890.3 kJ mol−1Based on the above thermochemical equations, the value of ∆rH° at 298 K for the reaction C(graphite)+2H2(g) → CH4(g) will be :a)+74.8 kJ mol−1b)+144.0 kJ mol−1c)−74.8 kJ mol−1d)−144.0 kJ mol−1Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Given C(graphite)+O2(g) → CO2(g) ;∆rH°=−393.5 kJ mol−1H2(g)+ 1/2O2(g) → H2O(l) ;∆rH° = −285.8 kJ mol−1CO2(g)+2H2O(l) → CH4(g)+2O2(g) ;∆rH°=+890.3 kJ mol−1Based on the above thermochemical equations, the value of ∆rH° at 298 K for the reaction C(graphite)+2H2(g) → CH4(g) will be :a)+74.8 kJ mol−1b)+144.0 kJ mol−1c)−74.8 kJ mol−1d)−144.0 kJ mol−1Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.
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