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A coil of 40 H inductance is connected in series with a resistance of 8 Ω and the combination is joined to the terminals of a 2 V battery. The time-constant of the circuit is
- a)5 s
- b)10 s
- c)20 s
- d)40 s
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A coil of 40 H inductance is connected in series with a resistance of ...
In case of an inductive resistive circuit, the time constant is given as L(eq)/R(eq).
So, in the given case
L(eq)=40H
R(eq)=8 ohm
Thus, time cons.=40/8=5s
Most Upvoted Answer
A coil of 40 H inductance is connected in series with a resistance of ...
To find the time constant of the circuit, we need to determine the time it takes for the circuit to reach 63.2% of its final steady-state current when a voltage is applied.
Formula for the time constant (τ) is given by:
τ = L/R
where L is the inductance of the coil and R is the resistance in the circuit.
Given:
Inductance (L) = 40 H
Resistance (R) = 8 Ω
Calculating the time constant:
τ = L/R
τ = 40/8
τ = 5 s
Therefore, the time constant of the circuit is 5 seconds.
Explanation:
- The time constant of a circuit is a measure of how quickly the circuit responds to changes in voltage or current.
- In an RL circuit, the time constant is determined by the ratio of the inductance to the resistance.
- A larger inductance or a smaller resistance will result in a larger time constant, indicating a slower response time.
- Conversely, a smaller inductance or a larger resistance will result in a smaller time constant, indicating a faster response time.
- In this circuit, with an inductance of 40 H and a resistance of 8 Ω, the time constant is calculated to be 5 seconds.
- This means that it will take approximately 5 seconds for the current in the circuit to reach 63.2% of its final steady-state value when a voltage is applied.
- The time constant is an important parameter in understanding the transient behavior of RL circuits and is often used to analyze the response of the circuit to different input signals or changes in the circuit parameters.
Formula for the time constant (τ) is given by:
τ = L/R
where L is the inductance of the coil and R is the resistance in the circuit.
Given:
Inductance (L) = 40 H
Resistance (R) = 8 Ω
Calculating the time constant:
τ = L/R
τ = 40/8
τ = 5 s
Therefore, the time constant of the circuit is 5 seconds.
Explanation:
- The time constant of a circuit is a measure of how quickly the circuit responds to changes in voltage or current.
- In an RL circuit, the time constant is determined by the ratio of the inductance to the resistance.
- A larger inductance or a smaller resistance will result in a larger time constant, indicating a slower response time.
- Conversely, a smaller inductance or a larger resistance will result in a smaller time constant, indicating a faster response time.
- In this circuit, with an inductance of 40 H and a resistance of 8 Ω, the time constant is calculated to be 5 seconds.
- This means that it will take approximately 5 seconds for the current in the circuit to reach 63.2% of its final steady-state value when a voltage is applied.
- The time constant is an important parameter in understanding the transient behavior of RL circuits and is often used to analyze the response of the circuit to different input signals or changes in the circuit parameters.
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A coil of 40 H inductance is connected in series with a resistance of 8 Ω and the combination is joined to the terminals of a 2 V battery. The time-constant of the circuit isa)5 sb)10 sc)20 sd)40 sCorrect answer is option 'A'. Can you explain this answer?
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