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A particle executing SHM along y-axis, which is described by y=10sin pi*t/4, phase of the particle at t=2 s is 1)pi/4 2)pi/2 3)pi/8 4)pi?
Most Upvoted Answer
A particle executing SHM along y-axis, which is described by y=10sin p...
Solution:

Given:

Amplitude, A = 10

Angular frequency, ω = π/4

Equation of SHM, y = Asin(ωt + φ)

Time, t = 2 s

To find:

Phase of the particle at t = 2 s

Solution Steps:


  • Compare the given equation of SHM with the standard equation of SHM, y = Asin(ωt + φ)

  • On comparing, we get ω = π/4 and A = 10

  • The phase of the particle at t = 2 s can be calculated using the formula, ωt + φ

  • Substituting the given values, we get the phase at t = 2 s as follows:


    • ωt + φ = π/4 * 2 + φ

    • ωt + φ = π/2 + φ

    • φ = (ωt + φ) - π/2

    • φ = (π/4 * 2 + φ) - π/2

    • φ = π/2 - φ/4

    • φ/4 = π/2

    • φ = 2π



Answer:

Therefore, the phase of the particle at t = 2 s is .
Community Answer
A particle executing SHM along y-axis, which is described by y=10sin p...
Ohho he is asking about the value of theta which is equal to w(omega)t= π/4×2
π /2 is correct answer ......
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