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The standard enthalpy of formation of NH3 is -4 6 .0 kJ mol -1. If the enthalpy of formation of H2 from its atoms is —436 kJ mol -1 and that of N2 is -712 kJ mol the average bond enthalpy of N—H bond in NH3 is: (in kJ/mol)
Correct answer is '352'. Can you explain this answer?
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The standard enthalpy of formation of NH3 is -4 6 .0 kJ mol -1. If the...
The balanced chemical equation for formation of NH3 would be as follows:
1/2N2(g) + 3/2H2(g)-->NH3(g)
The energy required to break required bonds for the formation of product is calculated as:
1/2 mole of N2 will require 712 kJmol^-1/2 = 356 kJ/mol
3/2 mole of H2 will require 3x 436 kJmol^-1/2 = 654 kJ/mol
Total energy require to break the bonds = (356 + 654) kJ/mol = 1010 kJ/mol
total energy of reaction = (total energy of bonds broken) - (total energy of bonds formed)
-46.3 kJ/mol =1010) kJ/mol - 3(N-H)
3(N-H) = 1010 kJ/mol + 46.3kJ/mol = 1056.3 kJ/mol
(N-H) = 1056.3 kJ/mol /3 = 352.1kJ/mol
Most Upvoted Answer
The standard enthalpy of formation of NH3 is -4 6 .0 kJ mol -1. If the...
Bond energy ( BE) of H2= 436 kj/ mol, BE of N2= 712 kj/ mol, ∆ Hf�( NH3) = -46 KJ/ mol.
∆ Hf�= ( BE) of reactant- BE( of product).
1/2 N2 + 3/2 H2------> 2 NH3
-46=(1/2�712 +3/2� 436) -3x
X=352 KJ/ mol
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The standard enthalpy of formation of NH3 is -4 6 .0 kJ mol -1. If the...
Not provided, we cannot calculate the enthalpy of formation of H2 from the given information.
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The standard enthalpy of formation of NH3 is -4 6 .0 kJ mol -1. If the enthalpy of formation of H2 from its atoms is —436 kJ mol -1and that of N2 is -712 kJ mol the average bond enthalpy of N—H bond in NH3 is: (in kJ/mol)Correct answer is '352'. Can you explain this answer?
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The standard enthalpy of formation of NH3 is -4 6 .0 kJ mol -1. If the enthalpy of formation of H2 from its atoms is —436 kJ mol -1and that of N2 is -712 kJ mol the average bond enthalpy of N—H bond in NH3 is: (in kJ/mol)Correct answer is '352'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The standard enthalpy of formation of NH3 is -4 6 .0 kJ mol -1. If the enthalpy of formation of H2 from its atoms is —436 kJ mol -1and that of N2 is -712 kJ mol the average bond enthalpy of N—H bond in NH3 is: (in kJ/mol)Correct answer is '352'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The standard enthalpy of formation of NH3 is -4 6 .0 kJ mol -1. If the enthalpy of formation of H2 from its atoms is —436 kJ mol -1and that of N2 is -712 kJ mol the average bond enthalpy of N—H bond in NH3 is: (in kJ/mol)Correct answer is '352'. Can you explain this answer?.
The standard enthalpy of formation of NH3 is -4 6 .0 kJ mol -1. If the enthalpy of formation of H2 from its atoms is —436 kJ mol -1and that of N2 is -712 kJ mol the average bond enthalpy of N—H bond in NH3 is: (in kJ/mol)Correct answer is '352'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The standard enthalpy of formation of NH3 is -4 6 .0 kJ mol -1. If the enthalpy of formation of H2 from its atoms is —436 kJ mol -1and that of N2 is -712 kJ mol the average bond enthalpy of N—H bond in NH3 is: (in kJ/mol)Correct answer is '352'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The standard enthalpy of formation of NH3 is -4 6 .0 kJ mol -1. If the enthalpy of formation of H2 from its atoms is —436 kJ mol -1and that of N2 is -712 kJ mol the average bond enthalpy of N—H bond in NH3 is: (in kJ/mol)Correct answer is '352'. Can you explain this answer?.
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