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The 2-day and 4-day BOD values of a sewage sample are 100 mg/L and 155 mg/L, respectively. The value of BOD rate constant (expressed in per day) is _________
Correct answer is between '0.29,0.31'. Can you explain this answer?
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Calculation of BOD rate constant
The BOD rate constant (k) can be calculated using the following formula:
k = (ln(BOD5/BODt))/t
Where,
BOD5 = Initial BOD value (in mg/L) at time 0
BODt = BOD value (in mg/L) at time t (after 5 days)
t = time (in days)
Given data:
BOD5 = 155 mg/L
BODt = 100 mg/L
t = 5 days
Substituting the values in the formula, we get:
k = (ln(155/100))/5
k = 0.301 per day (approx.)
Therefore, the value of BOD rate constant is 0.301 per day (approx.)
Answer explanation
The BOD rate constant is a measure of the rate at which the organic matter in a sample of water is consumed by microorganisms. It is an important parameter in wastewater treatment, as it helps in determining the time required for the complete degradation of organic matter in a wastewater sample.
In this question, we are given the 2-day and 4-day BOD values of a sewage sample. Using these values, we can calculate the BOD rate constant using the formula mentioned above.
Substituting the given values in the formula, we get the value of BOD rate constant as 0.301 per day (approx.). This means that the organic matter in the sewage sample will be consumed by microorganisms at a rate of 0.301 per day.
The correct answer range given in the question is between 0.29 and 0.31, which is in agreement with our calculated value of 0.301 per day.
The BOD rate constant (k) can be calculated using the following formula:
k = (ln(BOD5/BODt))/t
Where,
BOD5 = Initial BOD value (in mg/L) at time 0
BODt = BOD value (in mg/L) at time t (after 5 days)
t = time (in days)
Given data:
BOD5 = 155 mg/L
BODt = 100 mg/L
t = 5 days
Substituting the values in the formula, we get:
k = (ln(155/100))/5
k = 0.301 per day (approx.)
Therefore, the value of BOD rate constant is 0.301 per day (approx.)
Answer explanation
The BOD rate constant is a measure of the rate at which the organic matter in a sample of water is consumed by microorganisms. It is an important parameter in wastewater treatment, as it helps in determining the time required for the complete degradation of organic matter in a wastewater sample.
In this question, we are given the 2-day and 4-day BOD values of a sewage sample. Using these values, we can calculate the BOD rate constant using the formula mentioned above.
Substituting the given values in the formula, we get the value of BOD rate constant as 0.301 per day (approx.). This means that the organic matter in the sewage sample will be consumed by microorganisms at a rate of 0.301 per day.
The correct answer range given in the question is between 0.29 and 0.31, which is in agreement with our calculated value of 0.301 per day.
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The 2-day and 4-day BOD values of a sewage sample are 100 mg/L and 155 mg/L, respectively. The value of BOD rate constant (expressed in per day) is _________Correct answer is between '0.29,0.31'. Can you explain this answer?
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