KBr crystallises in face-centered cubic(fcc) crystal. The density and ...
KBr crystallises in face-centered cubic(fcc) crystal. The density and ...
Introduction:
KBr (Potassium Bromide) is a crystalline compound that forms a face-centered cubic (fcc) crystal lattice structure. In this structure, the potassium (K) ions and bromide (Br-) ions are arranged in a specific manner. The density and formula mass of KBr crystal provide valuable information to calculate the distance between K and Br- ions.
Given information:
- Density (ρ) = 2.65 g/cm³
- Formula mass (M) = 119 g/mol
Step 1: Calculate the number of KBr formula units in 1 cm³:
To find the number of formula units, we need to convert the density into units of g/cm³. Since the density is given as 2.65 g/cm³, we can assume that 1 cm³ of the crystal contains 2.65 grams of KBr.
So, the number of formula units (N) in 1 cm³ can be calculated using the formula:
N = ρ / M
Plugging in the given values:
N = 2.65 g/cm³ / 119 g/mol
Step 2: Calculate the edge length of the fcc unit cell:
In an fcc crystal lattice, there are 4 atoms per unit cell. The edge length (a) of the unit cell can be calculated using the formula:
a = (4 * M / ρ)^(1/3)
Plugging in the given values:
a = (4 * 119 g/mol / 2.65 g/cm³)^(1/3)
Step 3: Calculate the distance between K and Br- ions:
In an fcc crystal lattice, the K and Br- ions are arranged alternately along the edges of the unit cell. The distance between the K and Br- ions can be calculated using the formula:
distance = a / 2
Plugging in the value of a obtained from step 2:
distance = a / 2
Result:
The distance between K and Br- ions in the KBr crystal is obtained by following the above steps and calculations.