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What is the rate of simple reaction 2NO + O2 → 2 NO2 ; when the volume of the reaction vessel is doubled?
  • a)
    Will grow 8 times of its initial rate
  • b)
    Will grow to 4 times of its initial rate
  • c)
    Reduce to 1/8 times of its initial rate
  • d)
    Will reduce to 1/4 times of its initial rate
Correct answer is option 'C'. Can you explain this answer?
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What is the rate of simple reaction 2NO + O2 → 2 NO2 ; when the ...
Answer:
From Law of mass action, we know Rate of reaction
R1=k[NO]^2[O2] where k is the rate constant.
When the volume of the vessel is doubled, the concentration of the reactants will be halved.
New rate R2= k(1/2[NO]^2)(1/2[O2}= 1/8(R1)
By doubling the volume, the rate of reaction will become 1/8th of the previous rate.
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What is the rate of simple reaction 2NO + O2 → 2 NO2 ; when the ...
Rate of Simple Reaction with Doubled Volume

The rate of a simple reaction is dependent on the concentration of the reactants. When the volume of the reaction vessel is doubled, the concentration of the reactants is halved, which affects the rate of the reaction.

Effect on Rate of Reaction

The rate of the simple reaction 2NO + O2 → 2NO2 will be affected as follows:

- The rate of the reaction will reduce to 1/8 times its initial rate when the volume of the reaction vessel is doubled.

Explanation

- When the volume of the reaction vessel is doubled, the concentration of the reactants is halved. This is because the same amount of reactants is now present in a larger volume.
- The rate of the reaction is directly proportional to the concentration of the reactants. Therefore, when the concentration of the reactants is halved, the rate of the reaction also reduces by a factor of 2.
- Since the concentration of both NO and O2 is halved, the overall reduction in the rate of the reaction is by a factor of 2 x 2 = 4.
- Therefore, the rate of the reaction will reduce to 1/4 times its initial rate when the volume of the reaction vessel is doubled.

However, the question asks for the rate of the reaction in terms of the initial rate. Therefore, we need to calculate the reduction in the rate of the reaction in terms of the initial rate.

- The rate of the reaction is reduced by a factor of 4 when the volume is doubled.
- Therefore, the rate of the reaction will reduce to 1/4 times its initial rate.

Hence, the correct answer is option C, which states that the rate of the reaction will reduce to 1/8 times its initial rate.
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What is the rate of simple reaction 2NO + O2 → 2 NO2 ; when the volume of the reaction vessel is doubled?a)Will grow 8 times of its initial rateb)Will grow to 4 times of its initial ratec)Reduce to 1/8 times of its initial rated)Will reduce to 1/4 times of its initial rateCorrect answer is option 'C'. Can you explain this answer?
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What is the rate of simple reaction 2NO + O2 → 2 NO2 ; when the volume of the reaction vessel is doubled?a)Will grow 8 times of its initial rateb)Will grow to 4 times of its initial ratec)Reduce to 1/8 times of its initial rated)Will reduce to 1/4 times of its initial rateCorrect answer is option 'C'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about What is the rate of simple reaction 2NO + O2 → 2 NO2 ; when the volume of the reaction vessel is doubled?a)Will grow 8 times of its initial rateb)Will grow to 4 times of its initial ratec)Reduce to 1/8 times of its initial rated)Will reduce to 1/4 times of its initial rateCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is the rate of simple reaction 2NO + O2 → 2 NO2 ; when the volume of the reaction vessel is doubled?a)Will grow 8 times of its initial rateb)Will grow to 4 times of its initial ratec)Reduce to 1/8 times of its initial rated)Will reduce to 1/4 times of its initial rateCorrect answer is option 'C'. Can you explain this answer?.
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