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Reaction of 11.6 g of the aldehyde A with 462 mg of Wilkinson's catalyst provided 9.2 g of alkene B. The mole % of the catalyst used is ‘X’ and the yield of the reaction is ‘Y’. What is the value X+Y?

    Correct answer is '91'. Can you explain this answer?
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    Reaction of 11.6 g of the aldehyde A with 462 mg of Wilkinson's ca...
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    Reaction of 11.6 g of the aldehyde A with 462 mg of Wilkinson's catalyst provided 9.2 g of alkene B. The mole % of the catalyst used is ‘X’ and the yield of the reaction is ‘Y’. What is the value X+Y?Correct answer is '91'. Can you explain this answer?
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    Reaction of 11.6 g of the aldehyde A with 462 mg of Wilkinson's catalyst provided 9.2 g of alkene B. The mole % of the catalyst used is ‘X’ and the yield of the reaction is ‘Y’. What is the value X+Y?Correct answer is '91'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Reaction of 11.6 g of the aldehyde A with 462 mg of Wilkinson's catalyst provided 9.2 g of alkene B. The mole % of the catalyst used is ‘X’ and the yield of the reaction is ‘Y’. What is the value X+Y?Correct answer is '91'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Reaction of 11.6 g of the aldehyde A with 462 mg of Wilkinson's catalyst provided 9.2 g of alkene B. The mole % of the catalyst used is ‘X’ and the yield of the reaction is ‘Y’. What is the value X+Y?Correct answer is '91'. Can you explain this answer?.
    Solutions for Reaction of 11.6 g of the aldehyde A with 462 mg of Wilkinson's catalyst provided 9.2 g of alkene B. The mole % of the catalyst used is ‘X’ and the yield of the reaction is ‘Y’. What is the value X+Y?Correct answer is '91'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry. Download more important topics, notes, lectures and mock test series for Chemistry Exam by signing up for free.
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