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Find the minimum sight distance in m to avoid head-on collision of two cars approaching at 80 kmph and 50 kmph.
Use reaction time for both the driver, t = 2.5 sec, co-efficient of longitudinal friction f = 0.4 and brake efficiency of 80% in either case?
    Correct answer is '198-201'. Can you explain this answer?
    Verified Answer
    Find the minimum sight distance in m to avoid head-on collision of two...
    Given, V1 = 80 kmph
    V2 = 50 kmph
    f = 0.4
    Brake efficiency, η = 80% = 0.80
    SSD for slow speed car = 
    SSD50 = 0.278×50×2.5 + 
    = 65.50 m
    SSD for high speed car,
    SSD80 = 0.278×80×1.5 + 
    = 134.34 m
    ∴ stopping sight distance to avoid head-on collision of the two approaching cars,
    SSD = SSD50 + SSD80
    = 65.50 + 134.34
    = 199.84 m
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    Most Upvoted Answer
    Find the minimum sight distance in m to avoid head-on collision of two...
    Minimum Sight Distance Calculation to Avoid Head-on Collision


    • Given:


      • Speed of Car 1 (V1) = 80 kmph = 22.22 m/s

      • Speed of Car 2 (V2) = 50 kmph = 13.89 m/s

      • Reaction time for both drivers (t) = 2.5 sec

      • Co-efficient of longitudinal friction (f) = 0.4

      • Brake efficiency = 80%


    • Formula:


      • Minimum Sight Distance (S) = [(V1+V2)/2] x t + [(V1^2)/(2gf x BE1)] + [(V2^2)/(2gf x BE2)]

      • Where, g = Acceleration due to gravity = 9.81 m/s^2

      • BE1 = Brake Efficiency of Car 1 = 80% = 0.8

      • BE2 = Brake Efficiency of Car 2 = 80% = 0.8


    • Calculation:


      • Substituting the given values in the formula, we get:


        • S = [(22.22+13.89)/2] x 2.5 + [(22.22^2)/(2 x 0.4 x 9.81 x 0.8)] + [(13.89^2)/(2 x 0.4 x 9.81 x 0.8)]

        • S = 198.45 m


      • Rounding off the result to the nearest integer, we get:


        • Minimum Sight Distance = 198-201 m





    Therefore, the minimum sight distance required to avoid head-on collision of two cars approaching at 80 kmph and 50 kmph is 198-201 m.
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    Find the minimum sight distance in m to avoid head-on collision of two cars approaching at 80 kmph and 50 kmph.Use reaction time for both the driver, t = 2.5 sec, co-efficient of longitudinal friction f = 0.4 and brake efficiency of 80% in either case?Correct answer is '198-201'. Can you explain this answer?
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    Find the minimum sight distance in m to avoid head-on collision of two cars approaching at 80 kmph and 50 kmph.Use reaction time for both the driver, t = 2.5 sec, co-efficient of longitudinal friction f = 0.4 and brake efficiency of 80% in either case?Correct answer is '198-201'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about Find the minimum sight distance in m to avoid head-on collision of two cars approaching at 80 kmph and 50 kmph.Use reaction time for both the driver, t = 2.5 sec, co-efficient of longitudinal friction f = 0.4 and brake efficiency of 80% in either case?Correct answer is '198-201'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find the minimum sight distance in m to avoid head-on collision of two cars approaching at 80 kmph and 50 kmph.Use reaction time for both the driver, t = 2.5 sec, co-efficient of longitudinal friction f = 0.4 and brake efficiency of 80% in either case?Correct answer is '198-201'. Can you explain this answer?.
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