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The density of oak is 0.72g/cc.assuming oak to have empirical formula CH2O. A log of dimension 1×5×25cm^3 is completely burnt.what is the mass of water produced?
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The density of oak is 0.72g/cc.assuming oak to have empirical formula ...
Given information:
- Density of oak: 0.72 g/cc
- Empirical formula of oak: CH2O
- Dimensions of the log: 1×5×25 cm^3
Calculating the mass of the log:
To calculate the mass of the log, we need to find its volume. The volume of the log can be calculated using the formula:
Volume = Length × Width × Height
Substituting the given values, we get:
Volume = 1 cm × 5 cm × 25 cm = 125 cm^3
Next, we can calculate the mass of the log using the density formula:
Mass = Density × Volume
Substituting the given values, we get:
Mass = 0.72 g/cc × 125 cm^3 = 90 g
Stoichiometry of combustion:
The empirical formula of oak is CH2O, which means it contains one carbon atom, two hydrogen atoms, and one oxygen atom.
During the combustion of oak, the carbon in the log reacts with oxygen in the air to produce carbon dioxide (CO2), while the hydrogen in the log reacts with oxygen to produce water (H2O).
The balanced equation for the combustion of CH2O is:
CH2O + O2 -> CO2 + H2O
From the equation, we can see that for every one mole of CH2O burned, one mole of H2O is produced.
Calculating the moles of CH2O:
To calculate the number of moles of CH2O in the log, we need to convert the mass of the log to moles.
The molar mass of CH2O can be calculated as follows:
(1 carbon atom × atomic mass of carbon) + (2 hydrogen atoms × atomic mass of hydrogen) + (1 oxygen atom × atomic mass of oxygen)
Molar mass of CH2O = (1 × 12.01 g/mol) + (2 × 1.01 g/mol) + (1 × 16.00 g/mol) = 30.03 g/mol
Now, we can calculate the number of moles of CH2O in the log using the formula:
Moles = Mass / Molar mass
Substituting the given values, we get:
Moles = 90 g / 30.03 g/mol = 2.997 mol (approximately 3 mol)
Calculating the mass of water produced:
Since the ratio of CH2O to H2O is 1:1, we can conclude that for every 3 moles of CH2O burned, 3 moles of H2O are produced.
The molar mass of water (H2O) is:
(2 hydrogen atoms × atomic mass of hydrogen) + (1 oxygen atom × atomic mass of oxygen)
= (2 × 1.01 g/mol) + (1 × 16.00 g/mol)
= 18.02 g/mol
Therefore, the mass of water produced can be calculated using the formula:
Mass of water = Moles of H2O × Molar mass of H2O
Substituting the values, we get:
Mass of water = 3 mol × 18.02 g/mol =
- Density of oak: 0.72 g/cc
- Empirical formula of oak: CH2O
- Dimensions of the log: 1×5×25 cm^3
Calculating the mass of the log:
To calculate the mass of the log, we need to find its volume. The volume of the log can be calculated using the formula:
Volume = Length × Width × Height
Substituting the given values, we get:
Volume = 1 cm × 5 cm × 25 cm = 125 cm^3
Next, we can calculate the mass of the log using the density formula:
Mass = Density × Volume
Substituting the given values, we get:
Mass = 0.72 g/cc × 125 cm^3 = 90 g
Stoichiometry of combustion:
The empirical formula of oak is CH2O, which means it contains one carbon atom, two hydrogen atoms, and one oxygen atom.
During the combustion of oak, the carbon in the log reacts with oxygen in the air to produce carbon dioxide (CO2), while the hydrogen in the log reacts with oxygen to produce water (H2O).
The balanced equation for the combustion of CH2O is:
CH2O + O2 -> CO2 + H2O
From the equation, we can see that for every one mole of CH2O burned, one mole of H2O is produced.
Calculating the moles of CH2O:
To calculate the number of moles of CH2O in the log, we need to convert the mass of the log to moles.
The molar mass of CH2O can be calculated as follows:
(1 carbon atom × atomic mass of carbon) + (2 hydrogen atoms × atomic mass of hydrogen) + (1 oxygen atom × atomic mass of oxygen)
Molar mass of CH2O = (1 × 12.01 g/mol) + (2 × 1.01 g/mol) + (1 × 16.00 g/mol) = 30.03 g/mol
Now, we can calculate the number of moles of CH2O in the log using the formula:
Moles = Mass / Molar mass
Substituting the given values, we get:
Moles = 90 g / 30.03 g/mol = 2.997 mol (approximately 3 mol)
Calculating the mass of water produced:
Since the ratio of CH2O to H2O is 1:1, we can conclude that for every 3 moles of CH2O burned, 3 moles of H2O are produced.
The molar mass of water (H2O) is:
(2 hydrogen atoms × atomic mass of hydrogen) + (1 oxygen atom × atomic mass of oxygen)
= (2 × 1.01 g/mol) + (1 × 16.00 g/mol)
= 18.02 g/mol
Therefore, the mass of water produced can be calculated using the formula:
Mass of water = Moles of H2O × Molar mass of H2O
Substituting the values, we get:
Mass of water = 3 mol × 18.02 g/mol =
Community Answer
The density of oak is 0.72g/cc.assuming oak to have empirical formula ...
54 g
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The density of oak is 0.72g/cc.assuming oak to have empirical formula CH2O. A log of dimension 1×5×25cm^3 is completely burnt.what is the mass of water produced?
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The density of oak is 0.72g/cc.assuming oak to have empirical formula CH2O. A log of dimension 1×5×25cm^3 is completely burnt.what is the mass of water produced? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The density of oak is 0.72g/cc.assuming oak to have empirical formula CH2O. A log of dimension 1×5×25cm^3 is completely burnt.what is the mass of water produced? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The density of oak is 0.72g/cc.assuming oak to have empirical formula CH2O. A log of dimension 1×5×25cm^3 is completely burnt.what is the mass of water produced?.
The density of oak is 0.72g/cc.assuming oak to have empirical formula CH2O. A log of dimension 1×5×25cm^3 is completely burnt.what is the mass of water produced? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The density of oak is 0.72g/cc.assuming oak to have empirical formula CH2O. A log of dimension 1×5×25cm^3 is completely burnt.what is the mass of water produced? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The density of oak is 0.72g/cc.assuming oak to have empirical formula CH2O. A log of dimension 1×5×25cm^3 is completely burnt.what is the mass of water produced?.
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