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A compound H2X with molar weight 80g is dissolved in a solvent having density of 0.4 g/ml . Assuming no change in volume upon dissolution , the molality of 3.2 molar solutions is???
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A compound H2X with molar weight 80g is dissolved in a solvent having ...
In 3.2 molar solution,We have amount of solute = 3.2 molVolume of solution = 1.0 LSince there occurs no change in volume on dissolving solute,Volume of solvent = 1LMass of solvent = (1.0 L)(0.4 g m L^-1) = (10^3 mL)(0.4 g m L^-1) =400 g =0.4 kgMolality of the solution = 3.2/0.4 =8 mol kg-1
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A compound H2X with molar weight 80g is dissolved in a solvent having ...
Calculation of Molality of 3.2 Molar Solution
1. Calculate moles of H2X:
- Molar weight of H2X = 80g
- Given molarity = 3.2 mol/L
- Number of moles = Molarity x Volume (in L) = 3.2 mol/L x 1 L = 3.2 mol
2. Calculate mass of H2X:
- Mass = Number of moles x Molar weight = 3.2 mol x 80g/mol = 256g
3. Calculate mass of solvent:
- Mass of solution = Mass of solute + Mass of solvent
- Mass of solution = 256g (solute) + Mass of solvent
- Given density of solvent = 0.4 g/ml
- Volume of solvent = Mass of solvent / Density = Mass of solvent / 0.4 g/ml
4. Calculate molality:
- Molality (m) = Moles of solute / Mass of solvent (in kg)
- Moles of solute = 3.2 mol
- Mass of solvent (in kg) = (Mass of solvent in g) / 1000
- Substitute the values to find the molality of the solution
Therefore, the molality of the 3.2 molar solution can be calculated using the given information about the compound, its molarity, and the density of the solvent. By following the steps outlined above, you can determine the molality of the solution accurately.
1. Calculate moles of H2X:
- Molar weight of H2X = 80g
- Given molarity = 3.2 mol/L
- Number of moles = Molarity x Volume (in L) = 3.2 mol/L x 1 L = 3.2 mol
2. Calculate mass of H2X:
- Mass = Number of moles x Molar weight = 3.2 mol x 80g/mol = 256g
3. Calculate mass of solvent:
- Mass of solution = Mass of solute + Mass of solvent
- Mass of solution = 256g (solute) + Mass of solvent
- Given density of solvent = 0.4 g/ml
- Volume of solvent = Mass of solvent / Density = Mass of solvent / 0.4 g/ml
4. Calculate molality:
- Molality (m) = Moles of solute / Mass of solvent (in kg)
- Moles of solute = 3.2 mol
- Mass of solvent (in kg) = (Mass of solvent in g) / 1000
- Substitute the values to find the molality of the solution
Therefore, the molality of the 3.2 molar solution can be calculated using the given information about the compound, its molarity, and the density of the solvent. By following the steps outlined above, you can determine the molality of the solution accurately.
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A compound H2X with molar weight 80g is dissolved in a solvent having density of 0.4 g/ml . Assuming no change in volume upon dissolution , the molality of 3.2 molar solutions is???
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A compound H2X with molar weight 80g is dissolved in a solvent having density of 0.4 g/ml . Assuming no change in volume upon dissolution , the molality of 3.2 molar solutions is??? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A compound H2X with molar weight 80g is dissolved in a solvent having density of 0.4 g/ml . Assuming no change in volume upon dissolution , the molality of 3.2 molar solutions is??? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A compound H2X with molar weight 80g is dissolved in a solvent having density of 0.4 g/ml . Assuming no change in volume upon dissolution , the molality of 3.2 molar solutions is???.
A compound H2X with molar weight 80g is dissolved in a solvent having density of 0.4 g/ml . Assuming no change in volume upon dissolution , the molality of 3.2 molar solutions is??? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A compound H2X with molar weight 80g is dissolved in a solvent having density of 0.4 g/ml . Assuming no change in volume upon dissolution , the molality of 3.2 molar solutions is??? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A compound H2X with molar weight 80g is dissolved in a solvent having density of 0.4 g/ml . Assuming no change in volume upon dissolution , the molality of 3.2 molar solutions is???.
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