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A compound H2X with molar weight of 80g is dissolved in a solvent having density of 0.4 gml–1. Assuming
no change in volume upon dissolution, the molality of a 3.2 molar solution is
no change in volume upon dissolution, the molality of a 3.2 molar solution is
Correct answer is '8'. Can you explain this answer?
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A compound H2X with molar weight of 80g is dissolved in a solvent havi...
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To calculate the concentration of the H2X solution, we need to know the volume of the solvent that the compound is dissolved in. We can use the following formula:
Concentration = (mass of solute) / (volume of solution)
We know that the molar weight of H2X is 80g, which means that one mole of H2X weighs 80g. Therefore, the mass of one mole of H2X is 80g.
Let's say we dissolve one mole of H2X in the solvent. We need to calculate the volume of the solution that contains one mole of H2X. To do this, we can use the molarity formula:
Molarity = (moles of solute) / (volume of solution in liters)
We know that one mole of H2X weighs 80g, so the mass of H2X in the solution is 80g. We also know that the density of the solvent is 0.4 g/ml. Therefore, the volume of the solution that contains 80g of H2X is:
Volume = (mass of H2X) / (density of solvent) = 80g / 0.4 g/ml = 200 ml
Now we can calculate the concentration of the H2X solution:
Concentration = (mass of solute) / (volume of solution) = 80g / 200 ml = 0.4 g/ml
Therefore, the concentration of the H2X solution is 0.4 g/ml.
Concentration = (mass of solute) / (volume of solution)
We know that the molar weight of H2X is 80g, which means that one mole of H2X weighs 80g. Therefore, the mass of one mole of H2X is 80g.
Let's say we dissolve one mole of H2X in the solvent. We need to calculate the volume of the solution that contains one mole of H2X. To do this, we can use the molarity formula:
Molarity = (moles of solute) / (volume of solution in liters)
We know that one mole of H2X weighs 80g, so the mass of H2X in the solution is 80g. We also know that the density of the solvent is 0.4 g/ml. Therefore, the volume of the solution that contains 80g of H2X is:
Volume = (mass of H2X) / (density of solvent) = 80g / 0.4 g/ml = 200 ml
Now we can calculate the concentration of the H2X solution:
Concentration = (mass of solute) / (volume of solution) = 80g / 200 ml = 0.4 g/ml
Therefore, the concentration of the H2X solution is 0.4 g/ml.
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A compound H2X with molar weight of 80g is dissolved in a solvent having density of 0.4 gml–1. Assumingno change in volume upon dissolution, the molality of a 3.2 molar solution isCorrect answer is '8'. Can you explain this answer?
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A compound H2X with molar weight of 80g is dissolved in a solvent having density of 0.4 gml–1. Assumingno change in volume upon dissolution, the molality of a 3.2 molar solution isCorrect answer is '8'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A compound H2X with molar weight of 80g is dissolved in a solvent having density of 0.4 gml–1. Assumingno change in volume upon dissolution, the molality of a 3.2 molar solution isCorrect answer is '8'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A compound H2X with molar weight of 80g is dissolved in a solvent having density of 0.4 gml–1. Assumingno change in volume upon dissolution, the molality of a 3.2 molar solution isCorrect answer is '8'. Can you explain this answer?.
A compound H2X with molar weight of 80g is dissolved in a solvent having density of 0.4 gml–1. Assumingno change in volume upon dissolution, the molality of a 3.2 molar solution isCorrect answer is '8'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A compound H2X with molar weight of 80g is dissolved in a solvent having density of 0.4 gml–1. Assumingno change in volume upon dissolution, the molality of a 3.2 molar solution isCorrect answer is '8'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A compound H2X with molar weight of 80g is dissolved in a solvent having density of 0.4 gml–1. Assumingno change in volume upon dissolution, the molality of a 3.2 molar solution isCorrect answer is '8'. Can you explain this answer?.
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